Try to solve..

@tejashree-neQ3Bn • Oct 25, 2024

Oct 25, 2024

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There are 3 blue balls, 5 red balls and 4 black balls. The balls of same colour cannot be distinguished from each other, how many different selections can be made with at least one ball of each colour?

a) 4,096
b) 240
c) 60
d) 120

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ISHAN TOPRE

@ishan-nohePN • Mar 16, 2011

I think the answer is 4096.
If we select 1 from each category the we have 9 balls to select. And still we have 3 ! ways to select with our balls.
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Tejashree Katdare

@tejashree-neQ3Bn • Mar 16, 2011

There are 3 ways with blue balls---selecting 2 balls, or selecting 3 balls. Similarly, there are 5 ways with red balls and 4 with black balls.

Total number of ways = 3*5*4 = 60
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Hussanal Faroke

@hussanal-faroke-U5nNM8 • Mar 16, 2011

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