Tips for C Programmers

What is Output of following c snippet?
int main(){
char *s="Abhas";
printf("%s",s+ 2);
getch();
} Posted in: #Coffee Room

has
Explanation: In the above program role of %s is to display the string whose address is passed as an argument. This is how a standard printf statement works in c language. Now since we have passed s + 2 as an argument therefore first value of this expression is evaluated. Here ‘s’ would refer to address of first character in string ‘s’. Now printf would get address of third character (address of first character + 2) as argument so it will display the string starting from third position. Hence output would be ‘has’.

kingdavid

has
Explanation: In the above program role of %s is to display the string whose address is passed as an argument. This is how a standard printf statement works in c language. Now since we have passed s + 2 as an argument therefore first value of this expression is evaluated. Here ‘s’ would refer to address of first character in string ‘s’. Now printf would get address of third character (address of first character + 2) as argument so it will display the string starting from third position. Hence output would be ‘has’.

Ummm... don't you think there must be a * in front of s+2 to get the output "has" ? What i actually mean is, to get the output "has", it must be *(s+2)

Vishal0203

Ummm... don't you think there must be a * in front of s+2 to get the output "has" ? What i actually mean is, to get the output "has", it must be *(s+2)

*(s+2) will give you s[2] i.e. h..

has is correct