There are three different sets of parallel lines. 5 in the first set, 6 in the second and 4 in the t
Feel free to solve ..
There are three different sets of parallel lines. 5 in the first set, 6 in the second and 4 in the third.
If no three lines intersect at one point, then how many triangles are formed? No two lines in any two different sets are parallel to each other.
a) 60
b) 120
c) 30
d) none of these
There are three different sets of parallel lines. 5 in the first set, 6 in the second and 4 in the third.
If no three lines intersect at one point, then how many triangles are formed? No two lines in any two different sets are parallel to each other.
a) 60
b) 120
c) 30
d) none of these
Replies
-
ISHAN TOPREThe answer is 4 triangles. So I will go with option 'd' None of these. -
Tejashree KatdareThree parallel lines ,one from each set put together make a triangle, So the total number of triangles is
5*6*4 = 120 -
andyKaneThis is unfair. The parallel lines are similar and shouldn't be distinguished separately! All the parallel lines in one set are identical. SO you can't do 5*6*4 !!!
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