• Ankita

MemberAug 28, 2011

## TCS Latest Campus Placement Papers 2011 (New Pattern) With Solutions

As you all know TCS has changed the test taking pattern since last year.

The New TCS test has:
1. No of questions: 35
2. Test Duration: 80 Minutes
3. Type: Logical Reasoning.

I will attach a file of the latest questions here soon and we can discuss the solutions here.
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Here is the final questions list.

All the questions can be discussed here for solutions.
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• MemberAug 29, 2011

thanks. please provide infosys,accenture and wipro latest pattern with solutions.
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• MemberAug 29, 2011

Isn't it solved? Where are the solutions? Can we discuss the answers in some thread?

@AKD: Once this is solved, I am planning to host it in my Quiz Engine. What say?
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• MemberAug 29, 2011

thanks akd 😀

we've got TCS placement next monday 😀 i don't have the aptitude test so my friends will be able to use them 😀
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@CP: The doc file only has questions. We need to discuss the solutions here. Can you give it a head start?

I have more questions to share.

PS: Some answers can be found elsewhere on the net, but the answers are different everywhere, so we need to find full-proof solutions here.
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• MemberAug 29, 2011

i've solved some of those already. can we discuss them here itself? 😀
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Yeah, Please. Share the solutions here.

PS: It's highly likely that the same questions with different values will appear in the test.
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• MemberAug 29, 2011

Given 3 lines in the plane such that the points of intersection form a triangle with
sides of length 20, 20 and 30, the number of points equidistant from all the 3
lines is
• 4
• 1
• 0
• 3

solution:
answer is 1. and that point is called incentre.

explanation:
now take a triangle and inscribe a circle inside the triangle. the circle must touch all the sides of the triangle as shown in the figure.

the radius of the circle will equidistant from all sides since the circle touches all three sides. there exists only one such point... 😀

P.S: click the image for a larger size 😀
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• MemberAug 29, 2011

After the typist writes 12 letters and addresses 12 envelopes, she inserts the
letters randomly into the envelopes (1 letter per envelope). What is the probability
that exactly 1 letter is inserted in an improper envelope?
• 11/12
• 1/12
• 0
• 12/212

explanation:

if one letter is inside a wrong envelope then there should be another one too which is in the wrong envelope. so the event of one error is impossible. so probability is 0.
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@CP: A lot of people say the answer is 4, where 1 in-centre and 3 exi-centers are considered. (I have no idea about this 😐 )
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• MemberAug 29, 2011

There are two water tanks A and B, A is much smaller than B. While water fills at
the rate of one litre every hour in A, it gets filled up like 10, 20, 40, 80, 160 .. in
tank B. (At the end of first hour, B has 10 litres, second hour it has 20, and so
on). If 1/32 of B's volume is filled after 3 hours, what is the total duration required
to fill it completely?
• 10 hours
• 8 hours
• 7 hours
• 9 hours

explanation:

1/32 filled in 3 hours.
in the next hour it will double the content in it...
i.e. 1/16 in in 4 hours
1/8 in in 5 hours
1/4 in in 6 hours
1/2 in in 7 hours
full in 8 hours
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• MemberAug 29, 2011

@CP: A lot of people say the answer is 4, where 1 in-centre and 3 exi-centers are considered. (I have no idea about this 😐 )
check out this link: <a href="https://gogeometry.com/geometry/incenter_excenter_incircle_excircle.htm" target="_blank" rel="nofollow noopener noreferrer">TracenPoche Dynamic Geometry: Triangle: Incenter, Incircle, Excenter, Excircle, internal and external bisectors. College Geometry, SAT Prep. Elearning</a>ere three epicentres and incentre are drawn. the question asks for the point which is at the same time equidistant from all sides. the epicentres are not equidistant from all sides.
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Great. Do answer the gold coin questions and dart question with solutions. There has been a lot of confusion over them too.
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• MemberAug 29, 2011

A circular dartboard of radius 1 foot is at a distance of 20 feet from you. You
throw a dart at it and it hits the dartboard at some point Q in the circle. What is
the probability that Q is closer to the center of the circle than the periphery?
• 0.5
• 0.25
• 0.75
• 1

explanation:
the probability is= (area we need to consider)/ (total area of the dartboard) = (pi (r/2)^2)/(pi r^2) =.25

P.S: these solutions may be wrong. so CEans please correct them if mistake found.
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• MemberAug 30, 2011

are u sure this is the new pattern for tcs????????????
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@Lekhya: Yes, TCS just visited our campus and they followed this pattern. We don't think they will change it soon.
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• MemberAug 30, 2011

ok thank u😀😁
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• MemberAug 30, 2011

Which colg are u in????????????????????????
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• MemberAug 30, 2011

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Most of the questions are solved here by CEan-CivilPrincess, if you don't get some of the other questions, post them here.
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• MemberSep 1, 2011

Alok and Bhanu play the following min-max game. Given the expression N = 9 +
X + Y – Z where X, Y and Z are variables representing single digits (0 to 9), Alok
would like to maximize N while Bhanu would like to minimize it. Towards this end, Alok
chooses a single digit number and Bhanu substitutes this for a variable of her choice
(X, Y or Z). Alok then chooses the next value and Bhanu, the variable to substitute the
value. Finally Alok proposes the value for the remaining variable. Assuming both play
to their optimal strategies, the value of N at the end of the game would be
• 18
• 20
• 0.0
• 27
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• MemberSep 2, 2011

Hi, I will be facing the TCS online test on Sept 7, 2011 and I donot know from where to start my preparation for. Can anybody please help me.
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uppala.roshni
Hi, I will be facing the TCS online test on Sept 7, 2011 and I donot know from where to start my preparation for. Can anybody please help me.
Start preparing with the aptitude questions (basic mathematics and logical reasoning along with Data Interpretation and Sufficiency type questions). Interview would be mostly about programming, your project and some totally irrelevant questions: #-Link-Snipped-# 😐
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• MemberSep 3, 2011

can any1 attch the file of question of thoughtworks
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• MemberSep 3, 2011

one mistake in a problem that i solved.

CIVILPRINCESS
Given 3 lines in the plane such that the points of intersection form a triangle with
sides of length 20, 20 and 30, the number of points equidistant from all the 3
lines is
â€¢ 4
â€¢ 1
â€¢ 0
â€¢ 3

solution:
answer is 1. and that point is called incentre.

explanation:
now take a triangle and inscribe a circle inside the triangle. the circle must touch all the sides of the triangle as shown in the figure.

the radius of the circle will equidistant from all sides since the circle touches all three sides. there exists only one such point... 😀

P.S: click the image for a larger size 😀
CIVILPRINCESS
check out this link: <a href="https://gogeometry.com/geometry/incenter_excenter_incircle_excircle.htm" target="_blank" rel="nofollow noopener noreferrer">TracenPoche Dynamic Geometry: Triangle: Incenter, Incircle, Excenter, Excircle, internal and external bisectors. College Geometry, SAT Prep. Elearning</a>ere three epicentres and incentre are drawn. the question asks for the point which is at the same time equidistant from all sides. the epicentres are not equidistant from all sides.
the excentre is also to be considered since it will be equidistant from all the sides when they are extended. this i had not thought..

but now there is a new thing that i found.

if it is an equilateral triangle then the no of excentre points would be three so the total points would be= 1(incentre)+3(excentre) =4.
but for an isosceles triangle the no of excentres to be considered are just two. therefore no of points = 1+2 =3

sorry for the confusion guys 😀
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• MemberSep 3, 2011

Alok and Bhanu play the following min-max game. Given the expression N = 9 +
X + Y – Z where X, Y and Z are variables representing single digits (0 to 9), Alok
would like to maximize N while Bhanu would like to minimize it. Towards this end, Alok
chooses a single digit number and Bhanu substitutes this for a variable of her choice
(X, Y or Z). Alok then chooses the next value and Bhanu, the variable to substitute the
value. Finally Alok proposes the value for the remaining variable. Assuming both play
to their optimal strategies, the value of N at the end of the game would be
• 18
• 20
• 0.0
• 27
the answer for this would be= 20

reason: when we have it like x+y-z the maximum value would be 11 by cleverly placing the numbers. i'll post some examples for it in sometime. its just the same. just add the constant and 11. 😀
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• MemberSep 5, 2011

@ civil princes
can u provide pdf of urs solution....?? plz .. i m sittng 4 TCS on 8th... plz buddy hepl
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• MemberSep 9, 2011

a lady has fine gloves and hat-18 blue,32 red,25 yellow.the lights are out but she could make out its hat or glove in the dark.she takes out an item out of the closet only if she is sure tat it is a glove.how many glove smust she take out to make sure tat she has a pair of each colour????

pls some one ans this.....................
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• MemberSep 9, 2011

how come its 11 in the case of x+y-z

pls explain
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• MemberSep 9, 2011

hey i have a doubt ex-centre is also equdistant from all the three lines know then we have the answer 4 is it corect or not
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• MemberSep 9, 2011

since it is given as LINE it can be extendable so that we get 3 excentres and one incentres so answer is 4 otherwise if it is given as LINE SEGMENT ans is 1
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• MemberSep 9, 2011

if it is LINE it can be extendable so we get 3 ex-centres and 1 incentres so ans is 4. if it is LINE SEGMENT we cannot extend it so answer will be 1 incentre so ans is 1.
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• MemberSep 9, 2011

Have u selected
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• MemberSep 9, 2011

we have tcs on campus on 17th of this month. I came across this doubt when i am preparing for it. Pls clear my doubt
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• MemberSep 11, 2011

Hi Ceans,
Here s NDS placement papers #-Link-Snipped-#
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• MemberSep 17, 2011

hi guys.
i got placed in TCS.thanks for all as u ppl helped me in clearing all my doubts in apti questions.
thanks once again.
hoping the hear happy news from u tooo

bye ppl
all the best
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• MemberSep 18, 2011

lekhya
hi guys.
i got placed in TCS.thanks for all as u ppl helped me in clearing all my doubts in apti questions.
thanks once again.
hoping the hear happy news from u tooo

bye ppl
all the best
Congrats, but why don't you stay in touch with us... 😀
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• MemberSep 19, 2011

hi
ya sure.i will help all of u in clearing ur doubts.pls concentrate on ur technical stuff as most of us were interviewed in tat part

all the best ppl
bye
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• MemberSep 19, 2011

lekhya
hi
ya sure.i will help all of u in clearing ur doubts.pls concentrate on ur technical stuff as most of us were interviewed in tat part

all the best ppl
bye
Ha ha.. That's nice... 😀 Thankz, and am from TCS, an year experienced now... 😀
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• MemberSep 19, 2011

wow u are frm TCS ah?????????????????????????omg i never knew tat...........
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• MemberSep 21, 2011

hey i am placed in TCS.....very happy ........
my efforts since may,2011 all came true........😀
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• MemberSep 22, 2011

congrats dude😁
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• MemberSep 24, 2011

For the FIFA world cup, Paul the octopus has been predicting the winner of each
match with amazing success. It is rumored that in a match between 2 teams A
and B, Paul picks A with the same probability as A's chances of winning. Let's
assume such rumors to be true and that in a match between Ghana and Bolivia,
Ghana the stronger team has a probability of 2/3 of winning the game. What is
the probability that Paul will correctly pick the winner of the Ghana-Bolivia game?
• 5/9
• 1/9
• 2/3
• 4/9 somebody plz answer this one
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• MemberSep 24, 2011

take one team proability i.e ghana sa 2/3.

its complement is 1-(2/3)=1/3
bolivia its winning proability is 1/3
and losing is 2/3

not the equation is p(winingof ghana and losing of bolivia)+p(wining of bolivia and losing of ghana)=(4/9)+(1/9)=(5/9)
this is the ans

all the best.

u can clear apti but concentrate in ur technical part during interview.
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• MemberSep 25, 2011

thankx lekhya..

im also confused in these..plz help !!
A hollow cube of size 5 cm is taken, with a thickness of 1 cm. It is made of
smaller cubes of size 1 cm. If 4 faces of the outer surface of the cube are
painted, totally how many faces of the smaller cubes remain unpainted?
• 800
• 500
• 900
• 488

There are two boxes, one containing 10 red balls and the other containing 10
green balls. You are allowed to move the balls between the boxes so that when
you choose a box at random and a ball at random from the chosen box, the
probability of getting a red ball is maximized. This maximum probability is
• 1/2
• 3/4
• 37/38
• 14/19

10 people meet and shake hands. The maximum number of handshakes
possible if there is to be no "cycle" of handshakes is (A cycle of handshakes is a
sequence of k people a1, a2, ......, ak (k > 2) such that the pairs {a1, a2}, {a2, a3},
......, {ak-1, ak}, {ak, a1} shake hands).
• 7
• 6
• 8
• 9

36 people {a1, a2, ...., a36} meet and shake hands in a circular fashion. In other
words, there are totally 36 handshakes involving the pairs, {a1, a2}, {a2, a3}, ....,
{a35, a36}, {a36, a1}. Then size of the smallest set of people such that the rest
have shaken hands with at least one person in the set is
• 11
• 12
• 18
• 13
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• MemberSep 26, 2011

is this the whole pattern or we have other section on aptitude and English also?
because 35 questions in 80 mins is quite easy i guess..
only logical reasoning?????
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• MemberSep 26, 2011

ManishKumarVerma
is this the whole pattern or we have other section on aptitude and English also?
because 35 questions in 80 mins is quite easy i guess..
only logical reasoning?????
yup only one section. only logical puzzles...
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• MemberSep 27, 2011

thanks for the questions i will join you within 7 days after having a look over these questions
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• MemberSep 27, 2011

cube prob:

volume=5*5*5=125
then reduce 2cm
so v=3*3*3=27
now 125-27=98
find faces=98*6=588
gn 4 faces are painted so area=4*25=100
then 588-100=488

balls prob:
take 2 boxes
transfer 9 red balls to another box so total balls in green box is(9+10)=19
now p(red ball in box1)=1
p(red ball in box2)=9/19

p(selectin box)=1/2
now eqn is
1*1/2 + (9/19)*(1/2)

verify the method frm ur frnds once........

gn no cycle of handshakes so n-1=10-1=9

36 ppl
so the formula is n/3=36/3=12

check balls prob. once
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• MemberSep 29, 2011

5/9 friend
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• MemberJan 20, 2012

hiii ,,,can any 1n gimme the explanatn fo this...???
two vessels contain milk solutions ,,with milk and water in the ratio 2:11 in the first vessel and in the ratio of 5:9 in the second. in what ratio should the contents of these two vessels be mixed such that the resultant mixture has milk and water in the ratio 3:8??
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• MemberJun 24, 2012

Can any1 tell me hw to prep fr placemnts...tcs wl visit my colz in d cumng aug...wt sort of prep needed in tr round...
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• MemberJun 24, 2012

tcs pattern wil b consisting of 3 rounds...
1.written test consists of 35que 1hr time with .33 negtive marking fr each wrng ans
2.tr round -fr tat u need to b thorough vth ur prjct n lang(c,c++,java) ds n any 2 subs of ur fav
3. hr round as u knw testing ur communication levels...so practise fr tat vth ur frnds n u can also prctise by sitting infrnt of a mirror by ans mre sort of que
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• MemberJul 5, 2012

Alok and Bhanu play the following min-max game. Given the expression N = 9 +
X + Y – Z where X, Y and Z are variables representing single digits (0 to 9), Alok
would like to maximize N while Bhanu would like to minimize it. Towards this end, Alok
chooses a single digit number and Bhanu substitutes this for a variable of her choice
(X, Y or Z). Alok then chooses the next value and Bhanu, the variable to substitute the
value. Finally Alok proposes the value for the remaining variable. Assuming both play
to their optimal strategies, the value of N at the end of the game would be
• 18
• 20
• 0.0
• 27