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@anuraadha-57t1B5 • Apr 14, 2011
when a simply supported beam is acted upon by a concentrated load (W kN) at the centre and uniformly distributed load (w kN/m). the shear force and bending moment is as shown
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@anuraadha-57t1B5 • Apr 14, 2011
Sign conventions for a beam
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@civilprincess-308hDv • Apr 14, 2011
for the cantilevered beams the loading conditions and the respective SFD and BMD
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@anuraadha-57t1B5 • Apr 14, 2011
Always the support reactions are determined by the equation of equilibrium
sum of horizontal forces=0
sum of vertical forces=0
sum of moments= 0 -
@maria-flor-8cAkif • Apr 14, 2011
What do you call the load in parabolic??? -
@anuraadha-57t1B5 • Apr 14, 2011
I guess you are asking about the shape of beam. when a uniformly distributed load acts on a beam the resulting bending moment takes the shape of parabola. -
@maria-flor-8cAkif • Apr 14, 2011
nope. We have an exam..the load is already in parabolic and we need to draw the shear and moment diagram.... -
@civilprincess-308hDv • Apr 14, 2011
yeah there is a loading condition where the load is parabolic distributed.
it has no other names it is just parabolic load
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@civilprincess-308hDv • Apr 14, 2011
if we take the seismic load acting on the vertical face of dam or the forces due to waves they are all parabolically distributed. 😀 -
@maria-flor-8cAkif • Apr 14, 2011
Ah..ok. but, how can I solve that kind of problem???? I never expect it to be on our exam in Strength of Materials. -
@civilprincess-308hDv • Apr 14, 2011
well i've not solved a parabolic load too. 😔
but i'll refer my books and let you know 😀 -
@maria-flor-8cAkif • Apr 14, 2011
ok. I'll try to post the problem here.CIVILPRINCESSwell i've not solved a parabolic load too. 😔
but i'll refer my books and let you know 😀 -
@civilprincess-308hDv • Apr 14, 2011
yeah do that 😀maria florok. I'll try to post the problem here. -
@anuraadha-57t1B5 • Apr 18, 2011
The beam formulas under various loading conditions. -
@anuraadha-57t1B5 • Apr 18, 2011
statically indeterminate structure - It is a structure where the static equilibrium equations are insufficient for determining the internal forces and reactions on that structure.

Statically determinate structure - [FONT=verdana, geneva, helvetica]It is a structure which can be fully analyzed using the static equilibrium equations.[/FONT] e.g : remove the support B in above figure. -
@khelagor-XnweZz • May 27, 2011
Thanks Anuraadha!