stresses on inclined plane

viratvicky

viratvicky

@viratvicky-VVVtIh • Oct 27, 2024
sir,
i have got one silly doubt maybe that due to i am not so good in trigonometry.
My question is of forces on inclined plane while deriving stresses on an inclined plane.
Please find my question in attached file and try to respond as soon as possible.

thanks,
Vicky.
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  • omprakash patil

    omprakash patil

    @omprakash-Um9Ko0 • Oct 2, 2016

    Fn= Normal Stress i.e. perpendicular to plane
    Fs= Tangential stress or shear stress i.e. parallel to plane
    And Fn and Fs is perpendicular to each other where F is resultant stress so using Pythagoras Theorem
    F =√(Fn^2+Fs^2)
    And theta = tan inverse ( Fs/Fn)
    0