• samarjeetsaigal

MemberJul 30, 2010

Stiffness of Spring???

Q : If the stiffness of the spring is 10 N/m having 20 turns. Now if the spring is cut into 2 equal pieces, so what will be the stiffness of each spring?
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Replies
• MemberJul 30, 2010

Good question that tests your insight.
The standard formula is F = kx where k is the proportionality constant (spring constant) and x denotes the amount of deformation from the original length.
Look up Hooke's law of compression/stretching of a solid rod. You will notice that k corresponds to YA/L[sub]0[/sub] and that x corresponds to DL
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• MemberAug 1, 2010

thanks for explaining the formula... i don't know this answer, i only got the question not the answer???
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• MemberAug 2, 2010

You have to try first
Sorry
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• MemberAug 13, 2010

samarjeetsaigal
thanks for explaining the formula... i don't know this answer, i only got the question not the answer???
stiffness will be 20 N/m...its right na...?
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• MemberAug 13, 2010

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• MemberAug 16, 2010

Voltaire
hello..
f=kx..if f is constant and x (length) is half then k will be double..if m wrong then make me right..sorry..!!
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• MemberAug 16, 2010

No need to be sorry 😀

You are right

Hooke's law defines the spring constant as a characteristic of a spring which is defined as the ratio of the force affecting the spring to the displacement caused by it.
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• MemberAug 17, 2010

hello..
f=kx..if f is constant and x (length) is half then k will be double..if m wrong then make me right..sorry..!!
here X does not define the length of spring it defines the deformation of spring on applying load
in my view there should be other ans😕
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• MemberAug 17, 2010

I have to admit that I, too, struggled with this one because L[sub]2[/sub]/L[sub]1[/sub] is a ratio end I would have thought that the ratio would be the same for both coils. Apparently it is not! The shorter spring does not conform to the same ratio as the longer spring if the same force is applied. One has to think of it as a rubber band: a one metre band will stretch to say 2 metres while a [sup]1[/sup]/[sub]2[/sub] metre band of the same material will stretch to only say [sup]3[/sup]/[sub]4[/sub] metres if the same force is applied.
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• MemberAug 26, 2010

This is the helical spring stiffness formula:

If you cut into half, n is halved.. so k gets doubled
It can be correlated to the stiffness of a uniform bar in tension too (K=AE/L). L reduces, K increases.
Lots of things are easily available on this question in Google
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• MemberAug 28, 2010

Ya very good this is the correct explanation & answer of this question.

I m totaly agree with u.
In study of design of springs( m.d.) we have to use this equation
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• MemberJul 8, 2016

thanks for the answerwhich makes me to free from confusion
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• MemberJul 8, 2016

Thanks for the information
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