Solve This Number Riddle

Kaustubh Katdare

Kaustubh Katdare

@thebigk Oct 23, 2024
Someone sent me this puzzle via email. I believe it's easy to crack (I've not tried it yet).

A question for u, the one who solve the problem will write the name in the attached file. The password to open the attached spreadsheet is nothing but the solution to this riddle.

2

3

4

15

12

3

4

5

28

20

4

5

6

45

30

5

6

7

66

42

6

7

8

?

56

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  • vik001ind

    vik001ind

    @vik001ind-rOaCSy May 19, 2011

    ya, if I'm right, it's easy to crack... I didn't get the instruction you have given in the question. Should I write the solution here?
  • whiz.kid.aniket

    whiz.kid.aniket

    @whizkidaniket-5IiBCq May 19, 2011

    The list of numbers into five rows:
    coz see the pattern (single digit) (single digit) (single digit) (double digits) (double digits) <-- this repeats for five times
    2 3 4 15 12
    3 4 5 28 20
    4 5 6 45 30
    5 6 7 66 42
    6 7 8 ?? 56


    The column 15 28 45 66 is
    15= Second digit x (First digit + second digit)
    28=4 x 7
    45=5 x 9
    66=6 x 11
    so next will be
    91=7 x 13


    The final column:
    12=Second digit x third digit ( 3 x 4)
    20=4 x 5
    30=5 x 6
    42=6 x 7
    56=7 x 8

    Password is : 91 😁
  • ISHAN TOPRE

    ISHAN TOPRE

    @ishan-nohePN May 20, 2011

    The answer is 104. So the password is 104.

    Sorry mine is wrong answer. The correct answer is posted below which is 91. I have given the solution too.

    Nice job Aniket
  • Kaustubh Katdare

    Kaustubh Katdare

    @thebigk May 20, 2011

    Eh, the file wasn't required. Ignore the second line in question. 😐
  • ISHAN TOPRE

    ISHAN TOPRE

    @ishan-nohePN May 20, 2011

    Hehe, OK it seems that Biggie wants solution.

    So, let us consider the set of '5' the first three numbers are 2,3,4 the 3,4,5 then 4,5,6 etc in each set. The fourth number in each set is addition of previous two multiplied by the second number i.e.; (2+3)*3=15

    So I will modify my answer 91