simple algebraic puzzle .....
Q. xyz+xyz+xyz=zzz
Find the value of xyz?
condition: values of xyz must be same throughout the expression.
Find the value of xyz?
condition: values of xyz must be same throughout the expression.
Replies

Anoop Kumarx=1
y=8
z=5 
Abhishek Rawal
But that doesn't satisfies the equation.ianoopx=1
y=8
z=5
As per your answer, xyz=40, Hence LHS = 40+40+40 = 120. RHS = zzz = 5^3 = 125.
LHS != RHS 
Anoop Kumar185+185+185 = 555 😛

Abhishek RawalBloody hell!
I thought question is : x*y*z + x*y*z + x*y*z = z*z*z [^_^] 
rahul69
If that is the case, then :Abhishek RawalBloody hell!
I thought question is : x*y*z + x*y*z + x*y*z = z*z*z [^_^]
x=3;
y=4;
z=6;
xyz+xyz+xyz=(3*4*6+3*4*6+3*4*6)=216=6*6*6=z*z*z
😏 
Shailaja TiwariWow ,great you're absolutely right @ianoop.But how did you get this answer .I mean the logic if you could share would be of great help .I'd tried solving the question in several ways(including trial and error method too but couldn't get it .)
Such questions are generally asked in BARC's RMO. 
Abhishek Rawal@#LinkSnipped#
3xyz = zzz => xyz = zzz/3
Take value of zzz = 111,222,333 upto 999.
Only one will satisfy the condition & that is 555.
Hence 555/3 = 185
So, x=1, y=8 & z=5 
Anoop KumarI started from 3 digit number multiplied by 3 = zzz
start from unit place.
3*z should have z at the unit place.
start from possibilities 3*1=3, 3*6=18 you can come up with 3*5 = 15.
now you got 5 at unit place and carry 1 that means now you need a number with
3*y should have 4 at unit place, so adding a carry 1 will result 5.
and same way you can find value of x.
I hope this way is simple.
May be there Could be other simpler approach. 
boombastik85Rahul 69 is right! xyz is x*y*z, 185 is an interesting answer but does not fit into rules of algebra
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