Shortest C++ code to print odd numbers between 1 and 100

Manish Goyal

@manish-r2Hoep • Oct 26, 2024

Oct 26, 2024

1.9K

write the shortest code you can write to print all the odd no from 1 to 100?

Note:- Don't use google please

Like 0 Replies 21

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gaurav.bhorkar

@gauravbhorkar-Pf9kZD • Feb 28, 2011

main( )
{
for (int i = 1; i <= 100; i+=2)
cout << i;
}

I didn't execute it, by the way.
0
Manish Goyal

@manish-r2Hoep • Feb 28, 2011

can you think something different

i mean not using this and any modulus operator?
0
Reya

@reya-SMihdC • Feb 28, 2011

main()
{
for(int i=1;i<=100;i++)
{
if(i%2!=0)
cout<<i;
}}
0
Hussanal Faroke

@hussanal-faroke-U5nNM8 • Feb 28, 2011

main()
{
pirntf("13579111315........99");
}
0
Manish Goyal

@manish-r2Hoep • Feb 28, 2011

Interesting
Any other way friends
0
gaurav.bhorkar

@gauravbhorkar-Pf9kZD • Mar 1, 2011

Hussanal Faroke
main()
{
pirntf("13579111315........99");
}
Haha... but that will hurt your fingers 😀
0
rajesh_s

@rajesh-s-qqMLTP • Mar 1, 2011

main()
{
for(i=1;i<100;i++)
{
for(j=2;j<i;j++)
{
if(i%j!=0)
cout<<i;
}
}
}
0

PraveenKumar Purushothaman

@praveenkumar-66Ze92 • Mar 2, 2011

Heard of Structures? Using that we can do in this way... 😀

struct ZeroEven {
    unsigned num : 1;
}

int main(){
    ZeroEven ze;
    for (i=0; i<100; i++)
    {
        ze.num = i;
        if (ze.num != 0)
            cout<<i;
    }
    return 0;
}

Guys, do try this and say! 😀

Manish Goyal

@manish-r2Hoep • Mar 3, 2011

This is what i was looking for Nice logic buddy

Any other way
0
PraveenKumar Purushothaman

@praveenkumar-66Ze92 • Mar 3, 2011

goyal420
This is what i was looking for Nice logic buddy

Any other way
Thanx... 😀
0
rajesh_s

@rajesh-s-qqMLTP • Mar 3, 2011

is my logic not correct
0
gaurav.bhorkar

@gauravbhorkar-Pf9kZD • Mar 3, 2011
praveenscience
Heard of Structures? Using that we can do in this way... 😀
```
struct ZeroEven {
    unsigned num : 1;
}

int main(){
    ZeroEven ze;
    for (i=0; i<100; i++)
    {
        ze.num = i;
        if (ze.num != 0)
            cout<<i;
    }
    return 0;
}
```
Guys, do try this and say! 😀
Nice solution. I never thought of using bit fields.
0
PraveenKumar Purushothaman

@praveenkumar-66Ze92 • Mar 4, 2011

gaurav.bhorkar
Nice solution. I never thought of using bit fields.
He he 😛 Thanx... 😁
0
Sreekar B V

@sreekar-uzyqHj • Sep 18, 2014

main()
{
int i=1;
while((i<100)&&(i+=2))
printf("%d",i);
}
0

simplycoder

@simplycoder-NsBEdD • Sep 28, 2014

#include<stdio.h>
//simplycoder

int main(int argc,char**argv)
{
   int n=1;
  while(n<100)
  {
     if(n & 1 && printf("%d",n));
     n++;
  }
return 0;
}

Kaustubh Katdare

@thebigk • Sep 28, 2014

Without wanting to distract this discussion; I think the guys who used print got it all right. Someone gotta beat that!

Or we need to rephrase the problem statement?
0

Tim Rossiter

@tim-rossiter-7Fnjpg • Sep 29, 2014

int main(int n)  //init n=-1
{
     (n<99)?(printf("%d\n",main(n+2))):(n=n); //emote is colon left paren
     return(n);
}

Kaustubh Katdare

@thebigk • Sep 29, 2014

#-Link-Snipped-# - You may use [code] .... [/code] tags to enter code without having to deal with emoticons.

0
Tim Rossiter

@tim-rossiter-7Fnjpg • Sep 29, 2014

Thanks
0

Anoop Kumar

@anoop-kumar-GDGRCn • Sep 29, 2014

I don't know C++ but here is java logic

void printOddNumbers(int maxLimit) {
       for(int i=1; i <= maxLimit; i+=2){
            System.out.println("Odd : " +i);
    }
}

Number of iterations: maxLimit / 2 ;

avii

@avii-TGGs8o • Oct 2, 2014

well here's in Go, if that interests anyone:

package main

import "fmt"

func main() {
    for i := 1; i < 100; i+=2 {
        fmt.Println(i)
    }
}