Please can anybody explain how the frequency of a communication signal affect its propagation range?

While HF has high penetration power, thus it can easily send information to large distance. (Which means HF carries more information)

Also

**Power**plays major role in information transmission. larger the power, larger the distance covered.

In the case of visible light, waves of shorter wavelength/high frequency travels less (blue light) and those with larger wavelength/low frequency travels longer (red light) distances.

Isn't it the case with coomunication signals too. Besides those are all electromagnetic waves.

Which means Energy is directly proportional to frequency.

Low frequency have low energy, so less distance traveled & thus HF can travel long distance.

Correct me if I am wrong.

h= planck's constant

v= frequency of signal

So higher the frequency longer the distance you can transfer

Most of all this is not a good way to look into communication do tell in What form you are trying to transfer data

Digital or Analog format ?

I think, Digital signals cannot be transmitted between two antennas (i.e through air)Jeffrey SamuelDigital or Analog format ?

I use free space bearing in mind that so many factors affect signal quality in our atmosphere.

@Olu_Ola

speed= distance /time

speed=wavelength*frequency So, wavelength*frequency=distance/time

And, wavelength=distance/(time*frequency)

Frequency and distance are directly proportional the higher the frequency the more distance for the sound to dissipate th lower the frequency th shorter the distance for the sound to dissipate

Thanks

VHF 120MHz is great for long distance such as ground to air comms at an airport and can talk to planes miles away. UHF 450MHz is still good for distance but not as far and is good for penetration into buildings over VHF due to its smaller wavelength size compared to the size of construction materials.

Abhishek RawalE = hf

Which means Energy is directly proportional to frequency.

Low frequency have low energy, so less distance traveled & thus HF can travel long distance.

Correct me if I am wrong.

Total energy =n* hf

If we apply the same power for high and low frequency wave, the number of photon would be inversely proportional to the frequency. Thus more photons will increase the tranvel range im air at lower frequency

High hz more data

But there is a curve rely low go sHort but ground esh middle bonus of atmosphere and really high frequencies can go out to space

When you get into really high frequencies becomes more line of sight

First of all we need to understand the relation between the wavelength and frequency telling fw=c where f is the frequency, c is the speed of light, and w is the wavelength. f and w are inversely related. Let us see the order of arrangement of the EM waves such as starting from gamma waves, xray, infrared, visible, microwave amd radiowaves( sorry if i have missed any). And let us consider the visible band of the EM waves by which we all see the red light has the longest travel distance because its wavelength is the highest among all the visible colours. The famous example of the traffic light because of which red light was considered so that it would be seen to a longer distance so people stop the vehicle in time. Keeping this in mind the wavelength is highest for red and lowest for violet in the visible band and is arranged in the order red, orange, yellow, green, blue, violet( leaving out the intermediate colours).

So by this patter we see that to the right of visible band the wavelength decreases and to the left the wavelength increases. Meaning the X-ray has a better penetration ability as its frequency is low and wavelength is high. And gamma rays has the most penetrating ability of all as for an example X-ray is used to penetrate bones where as microwave and radio waves used in radar us to penetrate clouds. So the pentration ability increases with increase in wavelength which inturn means decrease of frequency helps in increase of penetration ability of a wave. And hence we can tell that the **propagation range is highest for the wave with highest wavelength and lowest frequency.**

based on dimensional analysis, relationship between wavelength and distance relates to one shared between frequency and duration but not any of the pair is similar. While frequency is cycles divided by time, wavelength is a derivative of distances divided by cycles. when the two are multiplies the cycles cancel out from which you get velocity, that is distance divided by time.

Firstly, Wavelength and frequency are two different properties of the signal. When a signal is propagated through a wire or free space, wavelength corresponds to the distance between to identical points(two identical points can be peak to peak points or any other similar points) in the adjacent cycles of the waveform.

Whereas the frequency of the signal is defined as the number of times one cycle of waveform is repeated per second. We know that velocity of a wave(v)= distance travelled by the wave(d) over a period of time(t). That is v = d/t. Here distance between two identical points in the wave is given by wavelength and frequency is inverse of time. Hence, the speed of light(c) is given by the product of frequency and wavelength.

Frequency is number of waves that pass through a given area at fixed time. It's unit is hertz.

Distance is the measurement of how far apart objects are. It's unit will be kilometer.

Frequency of sound is increased or decreased based on the distance between the objects. These are inversely propotional.

The relationship between wavelength and distance is similar to the relationship between frequency and duration, and no: neither pair is the same. You can see by using dimensional analysis. Wavelength is distance divided by cycles. Frequency is cycles divided by time.