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@amitbose-3q0iVf • Sep 2, 2009
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@vishnu-priya-L6wLMl • Sep 2, 2009
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@mrdon-92OwlG • Sep 2, 2009
Increase in flux decreases the speed but increases the torque. If torque is decreased by decreasing the field current the following sequences are found:
- <a href="https://en.wikipedia.org/wiki/Counter-electromotive_force" target="_blank" rel="nofollow noopener noreferrer">Counter Electromotive Force</a> drops instantly, the speed remaining constant because of the inertia of heavy armature.
- Due to decrease of EMF armature current I is increased because of I = (V â E)/R.
- A small decrease of flux is more than counterbalanced by a large increase of I which means net increase of torque.
- If torque increases the speed also increases.
where:
- N = revolutions per minute .i.e. motor speed
- K = proportional constant
- R = resistance of armature (<a href="https://en.wikipedia.org/wiki/Ohm" target="_blank" rel="nofollow noopener noreferrer">Ohm</a>)
- V = electromotive force (<a href="https://en.wikipedia.org/wiki/Volt" target="_blank" rel="nofollow noopener noreferrer">Volt</a>)
- I = current (<a href="https://en.wikipedia.org/wiki/Ampere" target="_blank" rel="nofollow noopener noreferrer">Ampere</a>)
- Φ = flux (<a href="https://en.wikipedia.org/wiki/Weber_%28unit%29" target="_blank" rel="nofollow noopener noreferrer">Weber %28Unit%29</a>)
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@mrdon-92OwlG • Sep 2, 2009
You will know it clearly by doing lab exercises perfectly.. -
@ashutoshglamour-YcpJXd • Sep 3, 2009
You can find the answers in book-B.L.THEREJA -
@cowboy-SpjNiz • Sep 3, 2009
I can find answer in any electrical machine book like b.L.Thareja volume 2.