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Quant thread for CAT 2011

Quant thread for CAT 2011

Reya

@reya-SMihdC • Oct 26, 2024

Oct 26, 2024

1.9K

Hi Guys,

Lets start discussing about math and quantitative problems. Please post all your math related problems and get it solved by our Crazyengineers 😀 You can also learn the easiest method of approach by discussing the answers!

I request all quant enthusiasts to post the questions here.Dont just give the answer alone. Post you method of approach too

Here goes my first question!

1.A dealer mixes tea costing Rs.8 per kg with tea costing Rs.7 per kg and sells the mixture at Rs.8 per kg with tea costing Rs.7 per kg. and sells the mixture at Rs.8 per kg.and earns a profit of Rs 15/2% on his sale price.In what proportion does he mix then?-

PS: Please convey your thanks by gives "likes".Dont spam this thread.This is my kind request.

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Reya

@reya-SMihdC • Jul 19, 2011

No takers??

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Ankita Katdare

@abrakadabra • Jul 19, 2011

I found this part a bit confusing:

sells the mixture at Rs.8 per kg with tea costing Rs.7 per kg. and sells the mixture at Rs.8 per kg

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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jul 20, 2011

Is the answer 19 : 24 ??

If yes I will give you the detailed explanation.

If my answer is incorrect, I dont want to confuse others with a invalid solution.

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Reya

@reya-SMihdC • Jul 20, 2011

@sandy: Your answer is wrong!

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yadavundertaker mohit

@yadavundertaker-0p3HBs • Jul 20, 2011

if the profit is 15/2 (7.5%) then i also get the same answer as ES 19:24

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Reya

@reya-SMihdC • Jul 20, 2011

No the answer is wrong! Anyone there to give the correct answer?

If not,I ll post the answer here.

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ISHAN TOPRE

@ishan-nohePN • Jul 21, 2011

Is the answer 2:15? 2 parts of Rs. 8 tea and 15 parts of Rs. 7 tea?
I will post the solution if you say it is correct.

Besides I found this part confusing too.

sells the mixture at Rs.8 per kg with tea costing Rs.7 per kg. and sells the mixture at Rs.8 per kg
Please clarify. 😀

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Reya

@reya-SMihdC • Jul 21, 2011

@Akd,Ishu: I just repeated the line again!

The question should be like

A dealer mixes tea costing Rs.8 per kg with tea costing Rs.7 per kg and sells the mixture at Rs.8 per kg and earns a profit of Rs 15/2% on his sale price.In what proportion does he mix then?-

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ISHAN TOPRE

@ishan-nohePN • Jul 21, 2011

Is the answer 611/16?

P.S: This is my last try. 😉

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Reya

@reya-SMihdC • Jul 21, 2011

Wrong!!

@CT & CP: where are you?

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cooltwins

@cooltwins-I5yJpZ • Jul 21, 2011

is it 2:3 ratio?

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Reya

@reya-SMihdC • Jul 21, 2011

@Madhu : You are rocking!

Can you please post your method of approach?

2.Find the no of triangles in an octagon having no side common with the octagon?

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cooltwins

@cooltwins-I5yJpZ • Jul 21, 2011

Method:
A dealer mixes tea costing Rs.8 per kg with tea costing Rs.7 per kg and sells the mixture at Rs.8 per kg and earns a profit of Rs 15/2% on his sale price.In what proportion does he mix then?

i think ES and Yadav made mistake in that bold part only...
15/2 = (SP-CP)/SP*100
so putting SP=8 => CP=7.4

then it is the usual allegation procedure to get the ratio 😀

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CIVILPRINCESS

@civilprincess-308hDv • Jul 21, 2011

is it 10? i'm not sure though...

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Sahithi Pallavi

@sahithi-oJZaYj • Jul 21, 2011

Is it 6? I am not sure.

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Reya

@reya-SMihdC • Jul 21, 2011

Both of them are wrong!

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ISHAN TOPRE

@ishan-nohePN • Jul 21, 2011

The answer is 16.

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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jul 21, 2011

It too think its 16.

8C3 - 32-8 = 56-40= 16.

@CP : Yes you are correct, the mistake was done in the bolded part 😀

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Reya

@reya-SMihdC • Jul 21, 2011

@ishu,sandy:Right!

3.

This expression is valid for a particular value of X? value of 5X?

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Reya

@reya-SMihdC • Jul 21, 2011

4. The ratio upto sum of n terms of the 2 A.Ps is 3n+2/4n-13.Find the ratio of 17th term of 2 A.Ps?

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ISHAN TOPRE

@ishan-nohePN • Jul 21, 2011

The value of 5X is -> 5*46656^(a square).

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Reya

@reya-SMihdC • Jul 21, 2011

ishutopreThe value of 5X is -> 5*46656^(a square).
Wrong ishu!

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ISHAN TOPRE

@ishan-nohePN • Jul 21, 2011

@Praveena: My last chance, either it is 2.78 or 2.18.

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Reya

@reya-SMihdC • Jul 21, 2011

@Ishu :wrong! Can you give me the value of x you arrived at?

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ISHAN TOPRE

@ishan-nohePN • Jul 21, 2011

2.78 is the value of X, which is also the value of natural base 'e'. So 5X is 13.591. 😔

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Reya

@reya-SMihdC • Jul 21, 2011

Ha Ha 😀

@ishu : Wrong!

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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jul 21, 2011

101:119 ??

Logarithms are my least priority!!

I have to practise a lot to get to my old momentum! I dont want to see my score card with less marks than previous years in DI and Quant.

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Reya

@reya-SMihdC • Jul 21, 2011

Your answer is right sandy!

Give me your method of approach!

Try to solve 3rd ques too.

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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jul 21, 2011

Approach:

we need , a1+16d1/a2+16d2 -----(1)

Given that ratio of sum of n numbers in both the series,

so, [2a1+(n-1)d1]/[2a2+(n-1)d2] = 3n+2/4n-13

To get (1) we have to substitute n=33 , which gives 101:119

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Reya

@reya-SMihdC • Jul 22, 2011

3.

This expression is valid for a particular value of X? value of 5X?
No takers for 3rd quest??

5.a0, a1, a2, a3..an are (n + 1) vertices of a regular polygon. And functions f(x) and g(x) are defined in such a way that. f(n) = Total number of diagonals in a regular polygon of (n + 1) sides and g(n) = Total number of triangles that can be made using the vertices of the (n + 1) sided regular polygon, as its vertices (None of the sides of the triangle should be common with that of polygon.) If f(n) = 5, then what is the value of g(n)?

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CIVILPRINCESS

@civilprincess-308hDv • Jul 22, 2011

qn. 3: is it 30?

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Reya

@reya-SMihdC • Jul 22, 2011

@CP: Right!

Post your method of approach!

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CIVILPRINCESS

@civilprincess-308hDv • Jul 22, 2011

the given expression can be written as a^(log (base 6) x ^ (log (base 4) a) ) = log (base 4) 256 = 4
(log (base 4) a)= (log (base 6) x ^ (log (base 4) a) = (log (base 4) a) * (log (base 6) x) => (log (base 6) x)=1 => x=6 ==> 5x =30 😀

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CIVILPRINCESS

@civilprincess-308hDv • Jul 22, 2011

English-ScaredIt too think its 16.

8C3 - 32-8 = 56-40= 16.
i don't understand the part in bold. can you please explain a little more in detail ? 😀

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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jul 22, 2011

If you consider a octagon, it has 8 points.
We can draw straight lines from one end to other end 5 lines, which gives you 4 traingles.

so , total 8 points which gives you 32 triangles with one side of the octagon.

Next from center you can draw 8 lines where you get 8 more triangles.

total of 40.

So, in an regular octagon you can have 8C3 triangles.

so its 16.

Hope I am clear, I am not sure of the process but this is what I got when I was trying 😀

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Reya

@reya-SMihdC • Jul 22, 2011

6.A car travels from B at a speed of 20 km/hr. The bus travel starts from A at a time of 6 A.M. There
is a bus for every half an hour interval. The car starts at 12 noon. Each bus travels at a speed of 25 km/hr. Distance between A and B is 100 km. During its journey, The number of buses that the car encounter is ?

PS: I'm not sure of the answer. I want to check my answer😔

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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jul 22, 2011

By counting I got the answer as 19 buses.

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cooltwins

@cooltwins-I5yJpZ • Jul 22, 2011

yeah i also got 19...

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Reya

@reya-SMihdC • Jul 22, 2011

I too got the same answer.

7.X is a number of more than 4 digits.The digits of X increase from left to right.What can be sum of digits of number 9X?

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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jul 22, 2011

5 = 0.

The number of diagonals for a n side regular polygon = n(n-3)/2
which gives n = 5.

So in order to draw a triangle without touching any of the side, we need more than 5 sides.

So there will be Zero triangles in this case.

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cooltwins

@cooltwins-I5yJpZ • Jul 22, 2011

praveena2117.X is a number of more than 4 digits.The digits of X increase from left to right.What can be sum of digits of number 9X?
is it 9? 😐

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Reya

@reya-SMihdC • Jul 22, 2011

yes you are right!

post your method of approach😀

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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jul 22, 2011

7. Answer is 9. For digits not more than 9.

Its a very big tedious process, I dont remember correctly. Will try posting it tomorrow.

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Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Jul 22, 2011

IS the answer for Question 5 correct?

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Reya

@reya-SMihdC • Jul 22, 2011

8.Sandeep is planning to attend wedding.He starts at a specific time and specific speed so as to be there at the exact time.he was driving for exactly 1 hour when his car had a flat tyre.He changed the tyre in 10 minutes.He started driving the remaining distance @ 40 km/h.he was late for the wedding by 30 minutes.If the puncture had happened 25 km later,he would be late for wedding by 20 min.what is the total dist. travelled by him?

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Reya

@reya-SMihdC • Jul 22, 2011

ASsuming the number is N.
N = a(n)a(n - 1).....a(0), where 0 < a(n) < a(n - 1) < .... < a(0) < 10
->0 < a(k) - a(k + 1) < 10 ----(1)
N = a(n)10ⁿ + .... + a(2)10² + a(1)10 + a(0)
9N = 9*10ⁿa(n) + .... + 900a(2) + 90a(1) + 9a(0)

Now, 9*10ⁿa(n) can be written as 10^(n + 1)a(n) - 10ⁿa(n)
9*10^(n - 1)a(n - 1) can be written as 10ⁿa(n - 1) - 10^(n - 1)a(n - 1)
.
.
900a(2) can be written as 1000a(2) - 100a(2)
90a(1) can be written as 100a(1) - 10a(1)
9a(0) can be written as 10a(0) - a(0)
Then subtract 10 and add 10 and keep all numbers of form 10^k together
Write coefficient of 10 as a(0) - a(1) - 1 and that of 1 as 10 - a(0)

So, it will become
-> 9N = 10^(n + 1)a(n) + 10ⁿ{a(n - 1) - a(n)} + ..... + 1000{a(2) - a(3)} + 100{a(1) - a(2)} + 10{a(0) - a(1) - 1} + (10 - a(0)}

Using (1)equ, we will get
Sum of digits of 9N = a(n) + {a(n - 1) - a(n)} + .. + {a(2) - a(3)} + {a(1) - a(2)} + {a(0) - a(1) - 1} + (10 - a(0))
= 10 - 1 = 9

@ES,CT : Is this the way you arrived at the result?

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cooltwins

@cooltwins-I5yJpZ • Jul 22, 2011

thats a good way to solve it... but no, i did not 😛 i tried it using examples like 12345, 123456, 1234567 and found all of them gave the same answer "9" 😛 trial and error method 😁

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CIVILPRINCESS

@civilprincess-308hDv • Jul 23, 2011

praveena2118.Sandeep is planning to attend wedding.He starts at a specific time and specific speed so as to be there at the exact time.he was driving for exactly 1 hour when his car had a flat tyre.He changed the tyre in 10 minutes.He started driving the remaining distance @ 40 km/h.he was late for the wedding by 30 minutes.If the puncture had happened 25 km later,he would be late for wedding by 20 min.what is the total dist. travelled by him?
is the answer 150 kms?

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Reya

@reya-SMihdC • Jul 23, 2011

@CP:wrong!

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CIVILPRINCESS

@civilprincess-308hDv • Jul 23, 2011

i think this is wrong.. but i'm getting 106.5

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