Member • Mar 16, 2008

sahanai have to multiply 2 n*m matrices using pointers and the most optimal solution is expected.
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Replies

Member • Mar 16, 2008
When you say pointers, do you meant that the matrices are implemented using linked list? Could you please provide more details on how the matrices are implemented.sahanai have to multiply 2 n*m matrices using pointers
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Member • Mar 17, 2008
yeah u can implement it by a linked list.Are you sure? This action cannot be undone. 
Member • Mar 17, 2008
if u need to multiply then check out this..this might help
#include<stdio.h> #include<conio.h> main() { int mtrx1[5][5],mtrx2[5][5],product[5][5],ro1,ro2,col1,col2; unsigned short int posblty; static unsigned short int call_main = 0; if(call_main == 0  call_main % 10 == 0) { clrscr(); printf("\nThis program will calculate the product of two matrices"); printf("\n~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~"); } call_main++; getnum(&ro1,1); getnum(&col1,3); getnum(&ro2,2); getnum(&col2,4); posblty = is_posble(col1,ro2); if(!posblty) { getch(); repeat(); } getmatrix(mtrx1,ro1,col1,1); getmatrix(mtrx2,ro2,col2,2); multiply(mtrx1,mtrx2,product,ro1,col2,col1); print_matrix(product,ro1,col2); find_trace(product,ro1,col2); repeat(); } getnum(num,message) int *num,message; { do { switch(message) { case 1: printf("\nEnter the number of rows in matrix 1:"); break; case 2: printf("\nEnter the number of rows in matrix 2:"); break; case 3: printf("\nEnter the number of columns in matrix 1:"); break; case 4: printf("\nEnter the number of columns in matrix 2:"); break; default: printf("\nEnter a number:"); } scanf("%d",num); } while(*num > 5); return; } is_posble(col_1,row_2) int row_2,col_1; { if(col_1 != row_2) { printf("\nThe multiplication of given matrices is not possible"); return(0); } else { return(1); } } getmatrix(array,row,column,mtrx_num) int *array[5],row,column,mtrx_num; { int i,j; printf("\nEnter matrix %d\n",mtrx_num); for(i = 0;i < row;i++) { for(j = 0;j < column;j++) { scanf("%d",array+(5*i+j)); } } return; } multiply(matrix1,matrix2,product,l,m,n) int *matrix1[5],*matrix2[5],*product[5],l,m,n; { int i,j,k,temp1,temp2,temp3; for(i=0;i < l;i++) { for(j = 0;j < m;j++) { *(product+(5*i+j)) = 0; for(k = 0;k < n;k++) { temp1 = *(matrix1+(5*i+k)); temp2 = *(matrix2+(5*k+j)); temp3 = *(product+(5*i+j)); *(product+(5*i+j)) = temp1 * temp2 + temp3; } } } return; } print_matrix(array,row,col) int *array[5]; { int i,j; printf("\nThe product is :"); for(i = 0;i < row;i++) { printf("\n"); for(j = 0;j < col;j++) { printf("%5d \t",*(array+(5*i+j))); } } return; }
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Member • Mar 18, 2008
hi friendster7,
i got your code.but is the most optimal?this code is designed for matrices which have a maximum of 5 rows and 5 columns right?so if i dont use a 5*5 matrix (say 3*3 ), its going to be a waste of space right?can we make it a little more optimal.how about dyanamic memory allocation?
please tell me if i have undserstood it wrongly.
another constraint i forgot to add in the question is that we cannot get the size of the matrix during runtime and then assign the subscript of the array.
ie something like
scanf("%d,%d",&rows,&col);
int array[row][col];
otherwise your code was really good.Are you sure? This action cannot be undone.