• JonathanAinsley

MemberJul 13, 2008

## Mechanics of gravity on the moon

Does someone on the moon fall at 1/6th of the speed on earth or at 2/5ths of the speed?

This has caused much more debate than I anticipated, so I wrote this vb app to prove it one way or another.

What do you think?
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Replies
• MemberJul 24, 2008

hmmm

93 views but only 4 visitors.

I would urge others who can do so to write themselves a similar application.

It is vital that one observes the difference between two objects dropped : one under lunar gravity, the other under earth gravity.

Then observe the difference between two similar objects that JUMP : one on the moon and one on the earth.

It is quite a remarkable insight comparing the 4 examples. Quite remarkable indeed!!!
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• MemberAug 21, 2008

bump
bump
bump
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• MemberNov 6, 2008

Using the constant acceleration eq: v^2 = vo^2 + 2a(x - xo) if you begin the fall with zero velocity and also call the initial x reference zero then the equation reduces to v = sqrt(2gx) for earth and v = sqrt(1/3 gx) for the moon. The ratio of v on earth to v on the moon reduces to sqrt(6) which is approximately 2.45. So when falling from the same distance on both the earth and the moon, the person willing be falling 2.45 times faster on earth than on the moon (at the same relative x position).
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• MemberNov 8, 2008

Falling = 2.5~ x difference

Jumping = 6 x difference

now see the video

then laugh at the fake moon landings

😎
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• MemberJun 3, 2009

Japanâ€™s Kaguya lunar orbiter took several pictures of the site, where Apollo 15 and Apollo 17 supposedly landed in 1971 and 1972. If the astronauts had ever landed there, they should have left a lot of equipment on the site, including the rovers, on which they traveled on the surface of the Earthâ€™s satellite. The pictures, which the Japanese rover took, showed not even the slightest hint of the US presence on the Moon.