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  • Load on a column

    zaveri

    Member

    Updated: Oct 25, 2024
    Views: 1.0K
    Columns are vertical members, For example: pillars.

    As far as beams are concerned. it is easy to represent the type of loads acting on them by means of free body diagrams. but how can this be done in the case of columns. ?

    Now consider this example:

    There is a clock hanging on the wall. considering the wall to be a column, how can the free body diagram of the system be drawn, to represent that the clock exerts a load on the wall, by virtue of its weight.

    The approach which i considered was, first to resolve the weight component of the clock into the two rectangular components( W*sin Theta and W*cos theta).

    How to proceed after this.
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  • sweet_honey

    MemberAug 28, 2012

    no answers yet!!😔
    plz answer this...
    me too waiting for the answer..
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  • zaveri

    MemberAug 28, 2012

    sweet_honey
    no answers yet!!😔
    plz answer this...
    me too waiting for the answer..
    Do you have any ideas about this ? share them out , even if they are wrong.
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  • hasini vaishnavi

    MemberAug 28, 2012

    i discussed it with my friend also and we were confused if the clock hung on the wall with a nail shud be considered or not..
    since its not mentioned
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  • zaveri

    MemberAug 28, 2012

    sweet_honey
    i discussed it with my friend also and we were confused if the clock hung on the wall with a nail shud be considered or not..
    since its not mentioned
    Yeah the nail should be considered as well. the weight of the nail can be compounded with that of the clock.
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  • sweet_honey

    MemberAug 28, 2012

    zaveri
    The approach which i considered was, first to resolve the weight component of the clock into the two rectangular components( W*sin Theta and W*cos theta).
    i didnt undrstand it because the weight of the clock wud be downwards and the angle wud be zero than how come u resolve it?
    may be m wrong.. plz correct me with your thoughts..
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  • zaveri

    MemberAug 28, 2012

    sweet_honey
    i didnt undrstand it because the weight of the clock wud be downwards and the angle wud be zero than how come u resolve it?
    may be m wrong.. plz correct me with your thoughts..

    no i was wrong. the weight acting would be downwards, and parallel to the column, so hence there is no point in resolving it.
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  • sweet_honey

    MemberAug 28, 2012

    zaveri
    no i was wrong. the weight acting would be downwards, and parallel to the column, so hence there is no point in resolving it.
    may be some concept of action and reaction wud work..
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  • zaveri

    MemberAug 28, 2012

    sweet_honey
    may be some concept of action and reaction wud work..

    this concept works everywhere, when it comes to any solid mechanics problem.

    what i want to know is , what the free body diagram of this system would look like
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  • sweet_honey

    MemberAug 28, 2012

    zaveri
    this concept works everywhere, when it comes to any solid mechanics problem.

    what i want to know is , what the free body diagram of this system would look like
    i actually didnt know the answer but tried to solve and didnt reach anywhere..
    so m looking forward for an appropriate answer..
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  • Saugata

    MemberAug 29, 2012

    Columns are placed directly under a load. The free body diagram will be most probably a straight-line in downward direction representing a compressive load which you can calculate by rankine's formula. Further depending on the length of the column you have to consider the buckling effect. In case of the wall the portion just underneath the clock will support the load as a column in addition to the rest portion of the wall which will act as a load bearing beam. This is just a proposition.
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