How many saucers on the table
Question: How many saucers can be accommodated on the table, without overlapping and not surpassing the table boundaries.
Explain your answer.
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Ha ha ha..😁 Atleast I was trying something and what you are doing waiting for a table whose diameter is 15 times the diameter of saucers and then try it? Tell? 😁silverscorpionI think shalini is trying all numbers from 1 to 225 in a trial and error method. 😀 😀
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Seems you made a mistake. Following this approach, we'll get the answer to be,durga168
the diametre is 15 times the diameter of the small bowl.
ie on diamter we can accomodate 15 bowls.
ie centre one bowl and on each side of the centre bowl 7 .
same is on the second perpendicular diameter
to have maximum utilisation of space i would prefer to put second row of bowls between 2 bowls of first row.
now I have this would be only for counting no of rows i can accomodate
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so I can arrange 7 rows above and below
so counting 15+14+13+12+11+10+9=84
on both sides = 168
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shalini_goel14@Scorpion thanks for the hint
I didn't took spaces into account.
Answer is 64 This time I think I am right. Right?
Explanation - See first coming from circumference - we can have 15 saucers at the circumfernce ok
How?
Circumference[sub]table[/sub] / Circumference[sub]saucer[/sub]
= pi * (15D) / pi * D
=15 saucers
Now again a circle of diameter 13D is created for you right?
How?
15D- D -D (each D from two ends of the diameter )
=13D
Then again applying same funda as above we can place 13 saucers in that circle
Continuing so...
We will get the series like following
15 + 13 +11 + 9 + 7+ 5 + 3 + 1
=Using AP formula ( (2 * a + (n-1) * d)* (n/2) )
= ( ( 2 * 1 + (8-1) * 2 ) * (8/2))
=64
I got answer as 64. Now I don't know how much correct it is ? 😔
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