How do I get the value of sin from this equation?

Aruwin

I have the answer but I don't see how Sin becomes like that.


Someone,please show me why is sin(u)= z/√(x²+z²)?I think there are some working in between this:
z = x tan(u)
tan(u) = z/x
sin(u) = z/√(x²+z²)

For you to understand this you should understand trigonomentry ratio well too.
Lets start like this, since tan(u)=z/x
then you draw a right-angle triangle. Choose any of the angles other than the angle 90" mark the chosen angle as 'u' then mark the opposite side of the chosen angle 'z' and adjacent you mark it 'x'
then from pythagoras we have that the square of the hypotanus is equal to x²+z² therefore ,
the hypothenus is √(x²+z²).
So now we have,
Opp=z
Adj=x
hyp=√(x²+z²)

hope you understand up to this length? If yes lets go on..

Sin(u)=opp/hyp

therefore, sin(u)=z/√(x²+z²)

hope this shows u how to get the value of sin(u) if tan(u)=z/x