Help with code
[FONT="] [/FONT][FONT="]Given a string and a number ‘n’, find the ‘n’th distinct repeating character. [/FONT]
[FONT="]For example, [/FONT]
[FONT="]Input:[/FONT]
[FONT="]Abracadabra, 1[/FONT]
[FONT="]Abracadabra, 2[/FONT]
[FONT="]Abracadabra, 3[/FONT]
[FONT="]Abracadabra, 4[/FONT]
[FONT="] [/FONT]
[FONT="]Output[/FONT]
[FONT="]a[/FONT]
[FONT="]b[/FONT]
[FONT="]r[/FONT]
[FONT="]null[/FONT]
[FONT="]For example, [/FONT]
[FONT="]Input:[/FONT]
[FONT="]Abracadabra, 1[/FONT]
[FONT="]Abracadabra, 2[/FONT]
[FONT="]Abracadabra, 3[/FONT]
[FONT="]Abracadabra, 4[/FONT]
[FONT="] [/FONT]
[FONT="]Output[/FONT]
[FONT="]a[/FONT]
[FONT="]b[/FONT]
[FONT="]r[/FONT]
[FONT="]null[/FONT]
Replies
-
Bharath51#include
#include
#include
void main()
{
char arr[10],c;
int n,i,count=0;
clrscr();
printf("Enter the string:");
gets(arr);
printf("enter the position\n");
scanf("%d",&n);
c=arr[n];
i=n-1;
for(i;i>=0;i--)
if(arr==c)
count++;
if(count>=1 )
printf("\nnull");
else
printf("\n%d",n);
getch();
}
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