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Heat exchange between Hot Water and Liquified Petrolium Gas

Dear All,
I want to have a heat exchange between Hot Water and Liquified Petrolium Gas (LPG: 60% propane and 40% butane) to vaporize LPG which is liquid state before heat transfer. Can anyone tell me how it works in reality? What is need of vaporizing it when it can be naturally vaporized? What is the fundamentals to use this?

Regards,
No liquid vaporizes unless the latent heat of vaporization is given. If you are thinking of the domestic gas cylinder, the evaporation rate is so small that ambient air can transfer enough heat through the cylinder wall. If the demand is high some heat exchange is needed. e.g. Cars running on LPG do require some active heat input. Indutrial use may need more.
zaveri • Jul 26, 2012
Hot water is the source which provides the latent heat of vaporization to LPG. you can build a simple counter-flow exchanger with LPG as the tube-fluid, and hot water as the shell-fluid.

But there are many other ways too.
How can I calculate the hot water temperature required for vaporizing LPG? Do you have the calculations for the same? Where I will get the thermal properties for LPG for certain temperature and pressure?

Calculate the total heat load as mL (m-mass of lpg/hr, L- latent heat of vaporization 104 KCal/kg) This should be matched by the heat lost by the hot water M(delT)(M - mass flow rate of water litre/hr, detlT- temp difference between inlet and outlet). Temperature need not be more than 70C. Design your heat exchanger based on these. If it is a stationary application, you may be able to buy a standard exchanger.
Thank You..
Dear All,
Which composition of LPG mixture (containing propane and butane (including 0%)) is better to use from chemical properties and availability point of view? Please tell me advantages and dis-advantages both.

Thank You.

Regards,