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@Sachin Jain • 21 Dec, 2010
Find the greatest number which divides 132,62,237 to leave same remainder.
@4M4N • 21 Dec, 2010 Answer:5
3 and 5 are only numbers that divide 32,162,237 and leave the same remainder. thus 5>3
Correct me if wrong
@Deepika Bansal • 21 Dec, 2010
4M4N
3 and 5 are only numbers that divide 32,162,237 and leave the same remainder. thus 5>3
Correct me if wrong
Though i dont know the answeres, but i think neither 3 nor 5 can be the answeres to this question. This is so because when 32,162,237 is divided by 3 or 5, we get 2 as remainder.
But the question says that the remainder should be same as the divisor....

@Sachin Jain • 21 Dec, 2010 @Deepika---> Remainder should be same in all cases.....

Can you please try the same for these numbers : -

62,132 and 237

Sorry 😔
@Deepika Bansal • 22 Dec, 2010 The method which i am following is as:

If I have to test a number 'x' for the solution then, (32,162,237-x)mod x=0.

and why are you sorry blunderboy....??
@4M4N • 22 Dec, 2010 @deepika is it compulsory that remainder should always be 0(according to ur method), as we can see remainder in the 1st example is non zero and can be anything
@Sachin Jain • 22 Dec, 2010 @Deepika
I said sorry because i gave wrong numbers first time.
Actually numbers are 62,132,237.

I am not getting your solution beacuse its very difficult to find the value of x.
As far as i think..
@Deepika Bansal • 22 Dec, 2010 Ok now I got it. You mean numbers are 62,132 and 237. I thought its a single number as 62132237.
Sorry.😔

4M4N now i also think 5 is the answere.......
@Sachin Jain • 22 Dec, 2010 No Guys,

62 % 35 =27 (35x1=35)

132%35=27 (35x3=105)

237 % 35=27 (35x6=210)

Now think of its solution.
@4M4N • 22 Dec, 2010 35 may be answer of 62,132,237 but i solved for 32,162,237 and its answer is :5
@Reya • 22 Dec, 2010
blunderboy
No Guys,

62 % 35 =27 (35x1=35)

132%35=27 (35x3=105)

237 % 35=27 (35x6=210)

Now think of its solution.
How did you find the value of x?
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