Function returning address of local variable
@amitsaste-V6mibl
•
Oct 21, 2024
Oct 21, 2024
1.3K
Hello,
I was just trying to return the address of local variable from function localAddress(). This generally will return the adress of local variable "local" for which memory will be deallocated after the execution of function localAddress(). What I think is, pointer variable "ptr" in function Victim() should contain some random values instead of real value of local variable in localAddress() since it is disallocated.
But in real this is not happening, rather ptr shows some memory address for temp.
Someone has any idea on this. thanks.
#include
I was just trying to return the address of local variable from function localAddress(). This generally will return the adress of local variable "local" for which memory will be deallocated after the execution of function localAddress(). What I think is, pointer variable "ptr" in function Victim() should contain some random values instead of real value of local variable in localAddress() since it is disallocated.
But in real this is not happening, rather ptr shows some memory address for temp.
Someone has any idea on this. thanks.
#include
<stdio.h>
int
*localAddress();
void
Victim();
void
main()
{
//Ampersand Bug
Victim();
}
}
void
Victim()
{
int *ptr;
ptr = localAddress(); //Pointee is returning address of local from localAddress() which was deallocated after execution of localAddress()
{
int *ptr;
ptr = localAddress(); //Pointee is returning address of local from localAddress() which was deallocated after execution of localAddress()
printf("\nptr is:%d",ptr);
}
int
*localAddress()
{
int local; //Local
{
int local; //Local
int *a = &local;
printf("\n%d is address of temp",a);
printf("\n%d is address of temp",a);
return(&local); //returning address of local which is going to be deallocated which is incorrect
}