Find the page no?
This question comes in this year nac test
give it a try
A person was given a task to calculate sum of all the page no's of a novel , but by mistake he added one page no twice ,therefore at the end he got sum 1000 ,now you have to find that page no which was added twice by him.
give it a try
A person was given a task to calculate sum of all the page no's of a novel , but by mistake he added one page no twice ,therefore at the end he got sum 1000 ,now you have to find that page no which was added twice by him.
Replies
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CIVILPRINCESSthe answer is twenty... 😁
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Manish Goyali dont know answer but according to me also answer is 20
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CIVILPRINCESSyeah i'm sure the answer is 20 anyone other answers:?:
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LeoHow come twenty
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CIVILPRINCESSi'm sorry i'm sorry the answer is 10. i made an arithmetic mistake. 😳 solution coming up
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Morningdot HabluAccording to me the answer is 11.
.
the page number starts from 0.
so the first term is 0.comman diff is 1.
so the right sum of the total page is (n(n-1))/2;
let he wrongly added the rth page so the rth page is (r-1){because zero comes first}.
.
now the final equation is like this {(n(n-1))/2}+{r-1}=1000.
now n(n-1)+2(r-1)=2000.
put n(n-1)=45*44;
so 2(r-1)=20;
r=11. -
CIVILPRINCESSBut we number the books with page numbers from 1 only right :?:
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CIVILPRINCESSmy solution is:
sum of 'n' page numbers starting from one is given by n(n+1)/2.
so n(n+1)/2<1000
n(n+1)<2000.
for n=44 we get the maximum value below 2000 ( which is 1980)
so the sum will be 44*45/2=990.
so 10 has been added twice -
Morningdot HabluOh shit.
But the process is right. -
Morningdot HabluYes by my process also the answer is 10.
final equation is like this (n(n+1))+2r=1000.
put n(n+1)=44*45.
2r=20 so the answer is 10. -
CIVILPRINCESSyeah the process is right.😀 so the answer is right or any other answers :?:
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LeoNo other answers 10 is right answer.
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Chaitali Sumita10 is the answer..
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HirenBarbhayaNice Explanation!!!
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sachinswethathe answer is 10.
sol:sum of first 44 numbers is 990.then we add 10 we get 1000.
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