Find the output of the following C Apptitude (2)

@rengaraj-89Rrct • Oct 26, 2024

Oct 26, 2024

1.4K

Sir / madam,
My question is

Find the output of the following

void main()
{
char *s="\12345s\n";
printf("%d",sizeof(s));
}

Advance Thanks,
R.Rengaraj
{Java Certification Quiz}
{On this forum my 22nd Question.}

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sarveshgupta

@sarveshgupta-txtmu5 • Dec 6, 2009

Can you please tell that don't we specify char with ' ' rather than " "

is it because we have taken it as a char pointer

seeing as if it can be said that the output will be 6

Is it the right answer?
0
gaurav.bhorkar

@gauravbhorkar-Pf9kZD • Dec 6, 2009

Can you please tell that don't we specify char with ' ' rather than " "

is it because we have taken it as a char pointer

seeing as if it can be said that the output will be 6

Is it the right answer?
The variable s is a pointer to a string. (its because of "").

The answer may be 4 as any pointer is 4 bytes long (correct me if I'm wrong).
0
dipen30

@dipen30-hGOPpa • Dec 6, 2009

compile this code and run it.

It gives the output 2.

can anyone explain how the output is 2? char contain 1 byte.
0
rengaraj

@rengaraj-89Rrct • Dec 6, 2009

sarveshgupta
Can you please tell that don't we specify char with ' ' rather than " "

is it because we have taken it as a char pointer

seeing as if it can be said that the output will be 6

Is it the right answer?
Sir,
How you say the output is 6 ? can you please explain.
R.Rengaraj
0
gaurav.bhorkar

@gauravbhorkar-Pf9kZD • Dec 7, 2009

dipen30
compile this code and run it.

It gives the output 2.

can anyone explain how the output is 2? char contain 1 byte.
The output depends on the compiler you use. 16 bit compilers store the pointers as 2 byte entity.

Which compiler you used?
0
sarveshgupta

@sarveshgupta-txtmu5 • Dec 7, 2009

rengaraj
Sir,
How you say the output is 6 ? can you please explain.
R.Rengaraj
Actually i counted the characters in the string

As we are calculating the length of the string so i counted the length of the string

but if we see for a normal char we know that in java char occupies 2 bytes

so if it has to consider char the output should be 2

Am I right?
0
dipen30

@dipen30-hGOPpa • Dec 7, 2009

I am using 16-bit compiler. so it gives output 2?
0
Saandeep Sreerambatla

@saandeep-sreerambatla-hWHU1M • Dec 7, 2009

dipen30
I am using 16-bit compiler. so it gives output 2?

Yes the pointer is 2 bytes irrespective of the type it is pointing to.

Depends on the compiler though.

Yes Gaurav said 16 bit gives 2 bytes.

32 bit gives 4 bytes.
0
gaurav.bhorkar

@gauravbhorkar-Pf9kZD • Dec 7, 2009

dipen30
I am using 16-bit compiler. so it gives output 2?
E_S is exactly right. A pointer is 2 bytes long in 16-bit compilers, and 4 bytes long in 32-bit compilers.

@sarveshgupta: Remember, it is not a character string, its a pointer to a character string.
0
sarveshgupta

@sarveshgupta-txtmu5 • Dec 7, 2009

Ok gaurav.. thanks
0
dipen30

@dipen30-hGOPpa • Dec 8, 2009

thanx gaurav & E-S
0
rengaraj

@rengaraj-89Rrct • Dec 8, 2009

Sir,
Have anybody tested on the compiler ???
I hope the solution will be 6.
R.Rengaraj
0
aishwarya mk

@aishwarya-hnVUq3 • Jul 10, 2016

dipen30
compile this code and run it.

It gives the output 2.

can anyone explain how the output is 2? char contain 1 byte.
answer is 2
because char data type 1 byte for * and another byte for s(address of array)
0