Dividing two numbers

Replies

• 

  srinivas_j

  hi!! dude the following code serves your purpose!!
  #include
  void main()
  {
  float a,b,r=0;
  printf("\n\n\tEnter Values of a & b :");
  scanf("%d%d",&a,&b);
  while(b*r <= a)
  r++;
  printf("\n\n\tAnswer is : %d ",r-1);
  }
  
  Have a Nice time!!(Note : It's for Integers!! ie, i've not taken floating point division to easy the task!!)
• 

  Sachin Jain

  Thats OK...Actually its a YAHOO interview question.
  I thought of doing like this :-
  We have to calculate y=A/B
  So take log of both sides
  log y=log(A/B)
  log y=log A - log B
  calculate log A - log B=x say
  Then take antilog both sides
  y=antilog (x)
  
  In this way we can find A/b without using / and % operator.
  Thats what i thought
• 

  silverscorpion

  srinivas_j

  hi!! dude the following code serves your purpose!!
  #include
  void main()
  {
  float a,b,r=0;
  printf("\n\n\tEnter Values of a & b :");
  scanf("%d%d",&a,&b);
  while(b*r <= a)
  r++;
  printf("\n\n\tAnswer is : %d ",r-1);
  }
  
  Have a Nice time!!(Note : It's for Integers!! ie, i've not taken floating point division to easy the task!!)

  Here, I think the printf statement should be outside the while loop!! 😀
• 

  srinivas_j

  no!! it's not inside d while loop!! it's outside itself try it out by Executing!!
• 

  prabait28

  Tell me Any other crct answer with simple concept.....
• 

  srinivas_j

  it's d simplest one & it takes very less cpu cycle time compared to ur other method!! & mor over logic is simple!