Difference b/w orifice plate & elbow taps for flow control and measurement

Difference b/w orifice plate & elbow taps for flow control and measurement

mohsinkhan987

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Updated: Oct 26, 2024

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difference b/w orifice plate & elbow taps for flow control and measurement

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Voltaire

Member • Oct 6, 2010

Yes
That is what happens when two seals fight over a grape
Please come back when you feel like asking a question
Peace

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mohsinkhan987

Member • Oct 7, 2010

if u dont knw the answer...then please dont reply..

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Saandeep Sreerambatla

Member • Oct 7, 2010

@Mohsin: Voltaire was saying that this is not a proper question!

For the differences you can google it , correct?
Please do some research and post questions appropriately.

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Voltaire

Member • Oct 7, 2010

If you don't know the question then don't ask

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mohsinkhan987

Member • Oct 7, 2010

sorry for ma misunderstanding dear!!
i m asking about the major difference b/w orifice plate and elbow taps when these are used for flow control

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Voltaire

Member • Oct 7, 2010

I think you mean: what is the difference between elbow and radius taps on a flow orifice?

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mohsinkhan987

Member • Oct 8, 2010

may be ur right...tell me the answer what understand of ma question..may be i wasnt able to make u understand

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Voltaire

Member • Oct 8, 2010

There are 4 types:
1. Flange taps - the pressure taps are directly on the flange in which the orifice sits
2. Pipe taps - 2½ pipe diameters upstream (u/s) and 8 diameters downstream (d/s)
3. Vena concentra taps - one pipe diameter u/s and at the vena concentra d/s (ca. 0.3 to 0.8 pipe diameters)
4. Corner taps - used in small diameter (usually < 2") pipes. Immediately adjacent to face plates

You should design for β of around 0.7 where the permanent pressure loss is typically about 0.6%. There is a square root relationship between dP and Q. Make sure the Reynolds number in the orifice never comes below 20,000. For incompressible fluids the discharge coefficient (C[sub]d[/sub]) can be taken as 0.61

Basic calculations according to Perry's:
Q=C[sub]d[/sub]A[sub]0[/sub]√[(2xΔP/ρ)/(1-β[sup]2[/sup])]
Where
Q in m[sup]3[/sup]/s
C[sub]d[/sub] in m
A[sub]0[/sub] the orifice diameter in m[sup]2[/sup]
P in Pa

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Voltaire

Member • Oct 9, 2010

Correction C[sub]d[/sub] is the dimensionless coefficient

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mohsinkhan987

Member • Oct 9, 2010

ok thanx alot dear..😀

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Voltaire

Member • Oct 9, 2010

Hahahaha
You're welcome dear 😉

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