Member • Aug 24, 2010
crazy new logical puzzles
1 of the balls is different in weight.
a weighing balance is provided.
what is the minimum possible checks we can find out the odd ball.??????
Member • Aug 24, 2010
Member • Aug 24, 2010
Member • Aug 24, 2010
Member • Aug 24, 2010
Member • Aug 24, 2010
Member • Aug 24, 2010
Member • Aug 24, 2010
Member • Aug 24, 2010
Member • Aug 25, 2010
Member • Aug 25, 2010
in question it is not mention that odd ball is heavier than others or lighter than others......so u cant proceed with havier group.......u have to decide first that faulty ball is havier than others or lighter than others....vineetdiit1st check 10 vs 10...if they are equal...then the remaining 1 is the odd ball
if its not then....
take the (10) set which has more weight....and again check for 5 vs 5......take the set(5) which has more weight...
check 2 vs 2 in that (5)set ...if equal then the remaining is the odd ball.....if not...
then check the 2 balls set which has more weight....
so to get correct always.....the answer is 4 checks
but the minimum possibility check is always ...................1
Member • Apr 1, 2011
Member • Apr 1, 2011