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  • Can someone give me a code that works as follows:

    Input :
    A word containing at max 10 letters.eg: "team"

    Output:
    The program should print the different words that can be formed using these letters.
    eg:team,tema,taem,tame,tmae,tmea, and so on. So the 4 letters give 4! that is 24 words.

    I am stuck up badly as I cant get any idea.Please someone help.😕
    Replies
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Replies

  • Prasad Ajinkya

    Member • Nov 21, 2008

    Ashutosh,
    Here's a hint - Use recursion or while loop.

    You need to -
    1. first divide the string into an array of characters ... so "team" becomes 't','e','a','m'
    2. Then just make a recursive function to output the letter

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  • Ashutosh_shukla

    Member • Nov 24, 2008

    Thanks your advice worked.I got some weird looking code but it worked in some cases.Can you please check it out.
    #include<iostream.h>
#include<conio.h>
#include<string.h>
char str[10];
static int index[10];
int len;
int count=0;
void anagram()
{
 if(count==len-1)
 {
  int p,q,flag;
  index[count]=0;
  for(;index[count]<len;index[count]++)
  {
   flag=1;
   for(p=0;p<=count;p++)
   {
    for(q=p+1;q<=count;q++)
    {
     if(index[p]==index[q])
      flag=0;
    }
   }
   if(flag)
   {
    for(p=0;p<len;p++)
    {
     cout<<str[(index[p])];
    }
    cout<<endl;
    getch();
   }
  }
 }
 else
 {
  count++;
  index[count-1]=0;
  for(;index[count-1]<len;index[count-1]++)
  {
   anagram();
  }
  count--;
 }
}
void main()
{
 clrscr();
 cout<<"Enter the word for which anagrams are to be found out : ";
 cin>>str;
 len=strlen(str);
 cout<<"\nThe anagrams found are as follows : \n";
 cout<<"Press enter to get next anagram : \n";
 anagram();
 getch();
}
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