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I brought a 200 rpm gear motor for my pick and place robot but I can't control it. Can I reduce its rpm to 60???? Please help.. .....0
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Member • Mar 12, 2013
Use gears on the op side I am not sure But I know that the gears can be used to both speed up and slow down
Couple a larger gear to the output of the geared motor
The gear you must have be capable of reducing the RPM that can be done by using a Larger gear in the output of the motor
Hey #-Link-Snipped-# #-Link-Snipped-# am I right in this do correct me if I am wrongAre you sure? This action cannot be undone. -
Member • Mar 12, 2013
Although another gear can be used, it will be a major hassle to make space for it, if it can be arranged at all. Instead I suggest controlling the voltage supply to the motor by using a potentiometer or a variable resistor in series with it.Are you sure? This action cannot be undone. -
Member • Mar 12, 2013
By adding resistance in series Can I get same torque as 60 rpm motor??? I'm asking because the bot should run on terrain.GurjapAlthough another gear can be used, it will be a major hassle to make space for it, if it can be arranged at all. Instead I suggest controlling the voltage supply to the motor by using a potentiometer or a variable resistor in series with it.Are you sure? This action cannot be undone. -
Member • Mar 12, 2013
Hey just check with the motor there are ways to control the Speed of the Motor
Check for articles relating to Speed COntrol of Motors that will surely help youAre you sure? This action cannot be undone. -
Member • Mar 12, 2013
Interesting question. I might do some analysis here by asking you what kind of load the motor is carrying and then telling you that since
Power= Torque x angular speed
and since your load hasn't changed, but you have decreased the voltage supply and hence the power, the angular speed must proportionately decrease, leaving the torque pretty much the same.
I refer you to <a href="https://lancet.mit.edu/motors/motors3.html" target="_blank" rel="nofollow noopener noreferrer">lancet.mit.edu</a> for more info.
PS. Remember, your choices in controlling the RPM might pretty much boil down to putting a resistor in series to the motor. In that case, you'll just have to make do, without considering a reduction in torque.Are you sure? This action cannot be undone. -
Member • Mar 12, 2013
ConquerorHey just check with the motor there are ways to control the Speed of the Motor
Check for articles relating to Speed COntrol of Motors that will surely help you
Ya I got a pdf on dc motor speed controlling. Thank youConquerorHey just check with the motor there are ways to control the Speed of the Motor
Check for articles relating to Speed COntrol of Motors that will surely help you
Even that gear idea looks nice, I will try.Are you sure? This action cannot be undone. -
Member • Mar 12, 2013
Geared control is having a limitation of larger size so do check it friendmallumatmariYa I got a pdf on dc motor speed controlling. Thank you
Even that gear idea looks nice, I will try.Are you sure? This action cannot be undone. -
Member • Mar 12, 2013
#-Link-Snipped-#
you were quite right about the gears.
#-Link-Snipped-#
you can reduce from 200 rpm to 60 rpm by using gears.
all you have to do is couple a larger gear to the existing gear on the motor shaft.
and as for the specifications of the larger, use this formula:
T1/T2 =N2/N1
where T1 = number of teeth on smaller gear (the one on the motor shaft).
T2 = number of teeth on the larger gear (which you will now couple)
N1 = speed of small gear (200 rpm in your case)
N2 = speed of larger gear (60 rpm in your case).
you know T1 N1 and N2. substitute them in the above formula and get the value for T2.
also if you want to save space, then replace the existing small gear with an even smaller gear, since this may also bring down the size of the large gear for the same speed ratio.Are you sure? This action cannot be undone. -
Member • Mar 12, 2013
Thank you, my first pick and place was flop because I not used any formula for arm, I will use that arm formula.GurjapInteresting question. I might do some analysis here by asking you what kind of load the motor is carrying and then telling you that since
Power= Torque x angular speed
and since your load hasn't changed, but you have decreased the voltage supply and hence the power, the angular speed must proportionately decrease, leaving the torque pretty much the same.
I refer you to <a href="https://lancet.mit.edu/motors/motors3.html" target="_blank" rel="nofollow noopener noreferrer">lancet.mit.edu</a> for more info.
PS. Remember, your choices in controlling the RPM might pretty much boil down to putting a resistor in series to the motor. In that case, you'll just have to make do, without considering a reduction in torque.
And for motor speed reduction I got a pdf,Are you sure? This action cannot be undone. -
Member • Mar 13, 2013
us this configuration to get the control of speed in PWM manner.Are you sure? This action cannot be undone. -
Member • Mar 13, 2013
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follow the circuit which is pwm controlling of motor speed.Are you sure? This action cannot be undone. -
Member • Mar 13, 2013
#-Link-Snipped-#Are you sure? This action cannot be undone.