Calculating Power from Cylinder
Hi all,
I'm wanting to calculate the instantaneous power of a piston. I know that usually P = Fv, where F is the force applied and v is the velocity. In this case, I'm pretty sure I need to use P = Fomega, where F is the force applied to the piston multiplied by the pressure and omega is the rotational velocity.
My question is
1) Is this formula correct?
2) How do I calculate the force?
I'm not a mechanical engineer, so please excuse my ignorance (my Google-fu hasn't really turned up anything of interest). I can provide more details about the piston if needed.
Thanks.
I'm wanting to calculate the instantaneous power of a piston. I know that usually P = Fv, where F is the force applied and v is the velocity. In this case, I'm pretty sure I need to use P = Fomega, where F is the force applied to the piston multiplied by the pressure and omega is the rotational velocity.
My question is
1) Is this formula correct?
2) How do I calculate the force?
I'm not a mechanical engineer, so please excuse my ignorance (my Google-fu hasn't really turned up anything of interest). I can provide more details about the piston if needed.
Thanks.
Replies
-
ZaraphraxSince nobody has replied, I thought I'd post this up here. I've done a bit of work with it and gotten some sort of procedure that I need to work backwards from.
I'm given:
-Crank angle at all times in the cycle
- Internal pressure at corresponding times
- Bore of the cylinder
- Stroke length
- Engine RPM
From this, I've tried to work out a way that I can calculate the power at any given time.
Working backwards, Pressure = Force x Area (where area is based on the bore), solving this for the Force.
Using the piston motion equation 0.5*stroke(1-cos theta), where theta is the corresponding crank angle, solve for the distance from top-dead-centre. Now multiply this by the force found previously, giving Torque.
Now that we have torque, multiply this by the angular velocity in radians per second (2*pi*rpm/60) giving power.
Sound reasonable?
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