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  • I am currently still going to school as an EE major, I am taking an electronics devices class, I seem to be having issues with this diagram:

    [​IMG]

    Sorry if it is sloppily drawn. It asks to Calculate the magnitude and phase angle of the circuit impedence, I know to find the impedence it is 1/(2PI*f*c), which is around 4 ohms. But how does one find the magnitude[convert to V which the formula works as (sqrt. Vc^2 + Vr^2)]. My question is this, would I need to change uF and f into V to get the magnitude or does it work like the magnitude formula but the result would not come out as voltage?
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  • Kaustubh Katdare

    Administrator • Oct 19, 2007

    Re: Hope this is the right place to ask this

    Raith, the most appropriate place for this question is our Electronics & Electrical Engineering section where we discuss everything related to electricity 😀 .

    -The Big K-
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  • Raith

    Member • Oct 20, 2007

    You're right but this is for newbies like me haha, I think I figured it out after reading over some sections of the book. Cheers!
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  • reachrkata

    Member • Oct 29, 2007

    Woow !!! need to brush up all the forgotten Basic electricity studied ages back during Engineering.

    But If I remember it right :
    expressing the impedance as a Complex number
    Z = R + jXc where Xc is 1/(2*Pi*f*C)

    then i think the magnitude is Sqrt (R^2 + Xc^2)
    and the phase i think is tan inverse (Xc/R)

    I only vaguely remember this, so people please correct me If i am wrong ???

    As i see, there is no need of any voltage. the frequency is given only for the impedance calculation.
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  • crook

    Member • Oct 29, 2007

    You can use subscripts and superscripts using special bb codes. Look #-Link-Snipped-#
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  • surendarkashyap

    Member • Mar 1, 2008

    magnitude is sqrt(R^2+Xc^2)
    phase is actuallt arc tan(Z/R)where Z=(Xc-Xl)[Xl is impedence due to inductor which is zero in this case)
    so phase(according to this prob )is arc tan(Xc/R)
    tats rite!!!!!!
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  • sauravgoswami

    Member • Mar 4, 2008

    Dude,hope u have got your ans,and solve it accordingly..welcome!!!
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