C Question

Replies

• 

  Kaustubh Katdare

  Is this a C programming question?
• 

  Manish Goyal

  Neha Kochhar

  What is the value of the expression (3^6) + (a^a)?
  
  a) 3 b) 5 c) 6 d) a+18 e) None
  
  
  
  I am Unable to solve this Out?
  Ans is 5 but how?
  Explain the Process

  I think you want to solve this expression using c right?
  ok
  If you don't input the value of a then it will take garbage value..now in order to obtain output 5 in the expression it should be like this
  (3^6)+(a^-a)
  ie a's power is a negative value
• 

  Neha Kochhar

  goyal420

  I think you want to solve this expression using c right?
  ok
  If you don't input the value of a then it will take garbage value..now in order to obtain output 5 in the expression it should be like this
  (3^6)+(a^-a)
  ie a's power is a negative value

  but how the value 5 is obtained?
  Please explain it .I did not get what you said
• 

  Hussanal Faroke

  is the 'a' defined, if no try it in another system? or u defined pls tell the value of a! u know in c 32767+1 is -32765
• 

  rishita

  Nice Goyal. But, we want detail solution. How we get the answer. Can you give detail step by step process of solution.
  Thanks for your solution.
  
  Regards,
  
• 

  vik001ind

  It doesn't matter whether a is defined or not.
  ^ stands for XOR. Xoring same bit return 0, different values return 1. Eg, 1^0 == 1 , 1^1 == 0
  Any int variable in C is 16 bit (16 bit compiler) or 32 bit (32 bit compiler). So, in any case whether it is defined or not, a will be a 16/32 bit pattern.
  Considering 16 bit compiler
  Bit pattern of 3 is 0000 0000 0000 0000 0011
  XOR
  Bit pattern of 6 is 0000 0000 0000 0000 0110
  Result is --> 0000 0000 0000 0000 0101 ---> 5
  
  a^a will always be equal to 0. Since we have bit pattern same in both cases.
  Therefore (3^6) + (a^a) = 5.