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C problem

[FONT="]#include[/FONT]
[FONT="] main()[/FONT]
[FONT="] {[/FONT]
[FONT="] clrscr();[/FONT]
[FONT="] printf(“%%%%%%%%%%%”);[/FONT]
[FONT="] getch();[/FONT]
[FONT="] }[/FONT]

What is the Output ?
Give Reason also......................

Replies

  • ish_nalini
    ish_nalini
    hey i think so it must be: %%%%%%%%%%%


    reason : printf prints as it is given inside the " "
  • pad
    pad
    %%%%%

    i.e. 5% as %% becomes % when used in printf as % is special here and is escaped. last % doesnt find a matching % so doesnt get printed.
  • ish_nalini
    ish_nalini
    pad
    %%%%%

    i.e. 5% as %% becomes % when used in printf as % is special here and is escaped. last % doesnt find a matching % so doesnt get printed.
    Excellent pad really thats a great Solution .. i hav not thinked about that ......Please keep posting these kind of brain killing posts
  • Pranny
    Pranny
    The output is %%%%%...

    cause has already been posted
  • ish_nalini
    ish_nalini
    Hello guys,
    I found the answer for this problem to be "%%%%%%"in Turbo C compiler...Any one to reason it??????
  • pad
    pad
    ish_nalini
    Hello guys,
    I found the answer for this problem to be "%%%%%%"in Turbo C compiler...Any one to reason it??????
    yes!

    specifications are not always implemented in products...
    find a true ANSI compliant version and try again
  • DEP
    DEP
    pad
    yes!

    specifications are not always implemented in products...
    find a true ANSI compliant version and try again

    hi pad,

    dont have ANSI compiler. So how about this idea of mine. You tell what is the anwer in ANSI compiler and i will try figure out the reason.

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