'C' code
int g=300*300/300;
cout<<"g="<
what would be the value of g? If you think the answer is you got is correct
Justify your answer.
cout<<"g="<
what would be the value of g? If you think the answer is you got is correct
Justify your answer.
Replies

Rocker
I'm not a C coder, but g = 109.223 ðŸ˜‰ravibharadwajint g=300*300/300;
cout<<"g="<
what would be the value of g? If you think the answer is you got is correct
Justify your answer.
Right?
Justification, 300*300 exceeds max. integer range which is 32768 to 32767 
amitpshuklaradio designing
i want to design a low power radio circuit, please give some ideas. 
sahanathe answer will be 81.
300*300/300
first 300*300 will be computed which is 90000.this is greater than 32767 which is the limit of data type int.hence 90000%32767 will be calculated which is 24466.now this will be divided with 300 (as the expression is 300*300/300). hence the answer is 81. 
crook
Sahan's explanation is better. I think the answer is 81. ravibharadwaj please post the correct answer.sahanathe answer will be 81.
300*300/300
first 300*300 will be computed which is 90000.this is greater than 32767 which is the limit of data type int.hence 90000%32767 will be calculated which is 24466.now this will be divided with 300 (as the expression is 300*300/300). hence the answer is 81. 
ravibharadwajGood one sahana and crook. Keep up the good work.
post in more puzzels 
rick
Is that the right answer though? Please confirm. I think 81 is the right answer.ravibharadwajGood one sahana and crook. Keep up the good work.
post in more puzzels 
ravibharadwajYup 81 is the right answer. Plz do post some c or c++ puzzles

MungutiRe: radio designing
I think you should start a new thread with a heading RADIO DESIGNING. Is it an AM or FM reciever 
naveeen reddy polimeraaccording to the BODMAS rule division '/' will execute and then * will execute
300*300/300=300*(300/300) 
simplycoderIt can be 300 aswel, did anyone verify it?
If yes, please share the os and which compiler and also the bit version of the compiler.
You are reading an archived discussion.
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