brain teaser

Replies

• 

  anandkumarjha

  what will be the output of the following codes any why????please explain....
  #include
  #include
  void main()
  {
  printf("%d",printf("%d %d",2,2)& printf("%d %d",2,2));
  getch();
  }
  
  
  
  
  #include
  #include
  void main()
  {
  printf("%d",printf("%d %d",2,2)& printf("%d %d",2,2));
  getch();
  }
  although thay look like same but they different from each other
• 

  sam_from_hell

  anandkumarjha

  main()
  {
  char thought[2][30]={"Don't walk infront me..","i am not follow"};
  printf("%c%c",*(thought[0]9),*(*(thought 0)5));
  }
  What will be the output of this code???

  Its throwing up a error "Expected ')' before numeric constant"
• 

  silverscorpion

  anandkumarjha

  what will be the output of the following codes any why????please explain....
  #include
  #include
  void main()
  {
  printf("%d",printf("%d %d",2,2)& printf("%d %d",2,2));
  getch();
  }
  
  
  
  
  #include
  #include
  void main()
  {
  printf("%d",printf("%d %d",2,2)& printf("%d %d",2,2));
  getch();
  }
  although thay look like same but they different from each other

  I dont see any difference between the first and the second.. I think both are one and the same..
  
  Anyhow, for the first program, the output is,
  
  2 2 2 2 1
  
  There are 2 printf statements inside the main printf statement.. printf statement returns the number of characters it has sent to the output buffer..
  So, both the inner printf's will return 2. It becomes '2 & 2' which is 1. So, 1 is printed last..