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@civilprincess-308hDv • Feb 5, 2010
i think it is the same as for the normal beams the only change must be the A.here we substitute A=pi*(d1^2-d2^2)/4
am i right :?: -
@vvishwaskumar-HA8DvG • Feb 5, 2010
sorry i don't get your notation....CIVILPRINCESSi think it is the same as for the normal beams the only change must be the A.here we substitute A=pi*(d1^2-d2^2)/4
am i right :?: -
@civilprincess-308hDv • Feb 5, 2010
it was just the formula for a area of cross section of hollow cylinder.here area is:
π (D^2 –d^2)
4
where D is the outer diameter
and d is inner diameter.
are you getting what i am trying to tell..:?: