arrangement problem

Replies

• 

  Prashanth_p@cchi

  Question may be confusing for many! It seems that no one is interested to make an attempt.
  Could you please provide us the answer?
• 

  Sagar07

  Well, it is obvious.... But, i wonder, how can one prove it????????
• 

  Ankita Katdare

  That is actually a bit difficult to prove.
  This a good sequence ->
  1, 10, 6, 2, 8, 7, 3, 5, 9, 4.
  None of the 3 consecutive numbers have a summation of less than 17 and it is at most 18.
• 

  Prashanth_p@cchi

  AbraKaDabra

  That is actually a bit difficult to prove.
  This a good sequence ->
  1, 10, 6, 2, 8, 7, 3, 5, 9, 4.
  None of the 3 consecutive numbers have a summation of less than 17 and it is at most 18.

  how about the one's marked above?
• 

  Ankita Katdare

  Prashanth_p@cchi

  how about the one's marked above?

  Oh yes. In a hurry I only checked these
  -
  1, 10, 6, 2, 8, 7, 3, 5, 9, 4.
  
  1,10,6
  10,6,2
  2,8,7
  8,7,3
  9,5,3
  5,9,4
  
  Now, that I think about it, since it is a circular arrangement 9,4,1 is also not proper.
• 

  Prashanth_p@cchi

  I think its impossible! but I might be wrong.
  
  Below is the least in terms of the entire sum, that can be used to satisfy the above criteria.
  
  6,6,5,6,6,5,6,6,5,6 which adds up to - 57
  
  But 1-10 adds up to 55.😔
• 

  Saandeep Sreerambatla

  Consider the numbers 1 to 10 are marked as 1 , x1, x2, ... , x9. Not necessarily in the sequence order.
  
  So the number are arranged randomly like this: 1,x1,x2,x3,x4,x5,x6,x7,x8,x9.
  
  We know that sum of numbers from 1 to 10 will add upto 55.
  
  so we will prove it in a negative way, if any of the groups above like (x1+x2+x3) or (x4+x5+x6) or (x7+x8+x9) will add up to < = (less than or equal to) 17. Then the sum 1+x1+...x9 will be <=52 which is wrong.
  
  So atleast one of the section should be greater than 17. (Hence proved 😀 )
• 

  Prashanth_p@cchi

  English-Scared

  Consider the numbers 1 to 10 are marked as 1 , x1, x2, ... , x9. Not necessarily in the sequence order.
  
  So the number are arranged randomly like this: 1,x1,x2,x3,x4,x5,x6,x7,x8,x9.
  
  We know that sum of numbers from 1 to 10 will add upto 55.
  
  so we will prove it in a negative way, if any of the groups above like (x1+x2+x3) or (x4+x5+x6) or (x7+x8+x9) will add up to < = (less than or equal to) 17. Then the sum 1+x1+...x9 will be <=52 which is wrong.
  
  So atleast one of the section should be greater than 17. (Hence proved 😀 )

  I agree...... I understood it wrong!