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    aksa

    Member

    Updated: Oct 26, 2024
    Views: 1.4K
    In the given figure, initially switch is closed. On opening the switch the charge that will flow through the battery will be [​IMG]

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  • reachrkata

    Member • Jan 6, 2010

    Zero (assuming ideal caps)!!!
    Anything you do with only capacitors on DC sources makes no difference.

    -Karthik
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  • piyushh

    Member • Jan 6, 2010

    hmm it will be zero ..because..just after or before opening the switch the capacitor(connected close to voltage source in series) will behave like an open circuit..finally no charge that will flow through the battery on opening the switch just after it was been closed for a long time(ideally infinte)
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