Answer this puzzle?

vinsocorp
@vinsocorp-4fscJ8 โ€ข Oct 25, 2024

a man has two cubes on his desk. every day he arranges both cubes so that the front faces show the current day of the month. what numbers are on the faces of the cubes to allow this? ๐ŸŽ‰

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  • Morningdot Hablu

    @morningdot-6Xuj4M • Aug 4, 2010

    On the first one 0,1,2,3,5,7 and on the 2nd one 0,1,2,4,6,8.

    Am i correct??

  • vinsocorp

    @vinsocorp-4fscJ8 • Aug 5, 2010

    Mohit its a good try. think how u show 9,19,29.one clue: one digit number u can show it by single cube,another cube is eliminated.

  • silverscorpion

    @silverscorpion-iJKtdQ • Aug 5, 2010

    Well, there are atmost 31 days in a month. So, till 31, there are 2 numbers which have repeated digits - 11 and 22.

    So, both the cubes must have 1 and 2, or they cant display 11 and 22.

    So, there ia 1 and 2 in both cubes. There are 8 digits remaining (3 4 5 6 7 8 9 0)
    There are eight sides remaining in the two cubes, totally..

    Hence, the remaining 8 digits can be filled in any manner in the remaining sides..

    For example,
    1 2 3 4 5 6 for the first cube,
    1 2 7 8 9 0 for the second is a possibility.

    Or, 1 2 4 6 8 0 for first,
    1 2 3 5 7 9 for second

    etc.. Any combination of the above will be fine, as long as both cubes have 1 and 2..

  • Morningdot Hablu

    @morningdot-6Xuj4M • Aug 5, 2010

    vinsocorpMohit its a good try. think how u show 9,19,29.

    For 9
    0 and reverse of 6
    for 19
    1 and reverse of 6
    for 29
    2 and reverse of 6.
    .....

    vinsocorpone clue: one digit number u can show it by single cube,another cube is eliminated.

    You doesn't mentioned this in question.
    And i tell you that it's a vary simle question when you alow for the above quotes.
    To make a question standard you have to reduce the probablity of finding a answer.

  • vinsocorp

    @vinsocorp-4fscJ8 • Aug 7, 2010

    Mohit u r very well in solving puzzles.here after i maintain standards in my question. ......what u doing...

  • marustech

    @marustech-CKSJnz • Aug 7, 2010

    very good .. but how we get 7,8,9 separateiy

  • marustech

    @marustech-CKSJnz • Aug 7, 2010

    great thinking

  • learner

    @learner-SrHIlM • Aug 7, 2010

    we can also do this sequence
    1st cube: 1,2,3,6,4 2nd cube: 0,1,2,5,7,8

  • Saandeep Sreerambatla

    @saandeep-sreerambatla-hWHU1M • Aug 20, 2010

    silverscorpionWell, there are atmost 31 days in a month. So, till 31, there are 2 numbers which have repeated digits - 11 and 22.

    So, both the cubes must have 1 and 2, or they cant display 11 and 22.

    So, there ia 1 and 2 in both cubes. There are 8 digits remaining (3 4 5 6 7 8 9 0)
    There are eight sides remaining in the two cubes, totally..

    Hence, the remaining 8 digits can be filled in any manner in the remaining sides..

    For example,
    1 2 3 4 5 6 for the first cube,
    1 2 7 8 9 0 for the second is a possibility.

    Or, 1 2 4 6 8 0 for first,
    1 2 3 5 7 9 for second

    etc.. Any combination of the above will be fine, as long as both cubes have 1 and 2..


    This is the straight forward simple answer!!

    ๐Ÿ˜€