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  • Answer this puzzle?

    vinsocorp

    Member

    Updated: Oct 25, 2024
    Views: 1.0K
    a man has two cubes on his desk. every day he arranges both cubes so that the front faces show the current day of the month. what numbers are on the faces of the cubes to allow this? 🎉
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Replies

  • Morningdot Hablu

    Member • Aug 4, 2010

    On the first one 0,1,2,3,5,7 and on the 2nd one 0,1,2,4,6,8.

    Am i correct??
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  • vinsocorp

    Member • Aug 5, 2010

    Mohit its a good try. think how u show 9,19,29.one clue: one digit number u can show it by single cube,another cube is eliminated.
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  • silverscorpion

    Member • Aug 5, 2010

    Well, there are atmost 31 days in a month. So, till 31, there are 2 numbers which have repeated digits - 11 and 22.

    So, both the cubes must have 1 and 2, or they cant display 11 and 22.

    So, there ia 1 and 2 in both cubes. There are 8 digits remaining (3 4 5 6 7 8 9 0)
    There are eight sides remaining in the two cubes, totally..

    Hence, the remaining 8 digits can be filled in any manner in the remaining sides..

    For example,
    1 2 3 4 5 6 for the first cube,
    1 2 7 8 9 0 for the second is a possibility.

    Or, 1 2 4 6 8 0 for first,
    1 2 3 5 7 9 for second

    etc.. Any combination of the above will be fine, as long as both cubes have 1 and 2..
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  • Morningdot Hablu

    Member • Aug 5, 2010

    vinsocorp
    Mohit its a good try. think how u show 9,19,29.
    For 9
    0 and reverse of 6
    for 19
    1 and reverse of 6
    for 29
    2 and reverse of 6.
    .....
    vinsocorp
    one clue: one digit number u can show it by single cube,another cube is eliminated.
    You doesn't mentioned this in question.
    And i tell you that it's a vary simle question when you alow for the above quotes.
    To make a question standard you have to reduce the probablity of finding a answer.
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  • vinsocorp

    Member • Aug 7, 2010

    Mohit u r very well in solving puzzles.here after i maintain standards in my question. ......what u doing...
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  • marustech

    Member • Aug 7, 2010

    very good .. but how we get 7,8,9 separateiy
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  • marustech

    Member • Aug 7, 2010

    great thinking
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  • learner

    Member • Aug 7, 2010

    we can also do this sequence
    1st cube: 1,2,3,6,4 2nd cube: 0,1,2,5,7,8
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  • Saandeep Sreerambatla

    Member • Aug 20, 2010

    silverscorpion
    Well, there are atmost 31 days in a month. So, till 31, there are 2 numbers which have repeated digits - 11 and 22.

    So, both the cubes must have 1 and 2, or they cant display 11 and 22.

    So, there ia 1 and 2 in both cubes. There are 8 digits remaining (3 4 5 6 7 8 9 0)
    There are eight sides remaining in the two cubes, totally..

    Hence, the remaining 8 digits can be filled in any manner in the remaining sides..

    For example,
    1 2 3 4 5 6 for the first cube,
    1 2 7 8 9 0 for the second is a possibility.

    Or, 1 2 4 6 8 0 for first,
    1 2 3 5 7 9 for second

    etc.. Any combination of the above will be fine, as long as both cubes have 1 and 2..

    This is the straight forward simple answer!!

    😀
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