@Anoop Kumar • 01 Dec, 2012 • 3 likes

Simplest explanation! Ever wondered why does this equation hold true? Check out the explanation -

edit: typo mistake in heading, please correct to

edit: typo mistake in heading, please correct to

*taught.*
@Ramani Aswath • 08 Dec, 2012
The Maharashtrian mathematecian Bhaskara II gave an interesting algebraic proof of the pythagorean Theorem:

Proof #4

The fourth approach starts with the same four triangles, except that, this time, they combine to form a square with the side (a + b) and a hole with the side c. We can compute the area of the big square in two ways. Thus

(a + b)² = 4·ab/2 + c²

simplifying which we get the needed identity.

A proof which combines this with proof #3 is credited to the 12th century Hindu mathematician Bhaskara (Bhaskara II):

Here we add the two identities

c² = (a - b)² + 4·ab/2 and

c² = (a + b)² - 4·ab/2

which gives

2c² = 2a² + 2b².

The latter needs only be divided by 2.

https://www.cut-the-knot.org/pythagoras/index.shtml

TEachers must make it interesting to students.

Proof #4

The fourth approach starts with the same four triangles, except that, this time, they combine to form a square with the side (a + b) and a hole with the side c. We can compute the area of the big square in two ways. Thus

(a + b)² = 4·ab/2 + c²

simplifying which we get the needed identity.

A proof which combines this with proof #3 is credited to the 12th century Hindu mathematician Bhaskara (Bhaskara II):

Here we add the two identities

c² = (a - b)² + 4·ab/2 and

c² = (a + b)² - 4·ab/2

which gives

2c² = 2a² + 2b².

The latter needs only be divided by 2.

https://www.cut-the-knot.org/pythagoras/index.shtml

TEachers must make it interesting to students.

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