8085 microprocessors

kaniranjith

kaniranjith

@kaniranjith-PZ0NrJ Oct 26, 2024
i have a doubt that though 8085 is a 8-bit processors why do we give input as a two 4-bit values?😒

Replies

Welcome, guest

Join CrazyEngineers to reply, ask questions, and participate in conversations.

CrazyEngineers powered by Jatra Community Platform

  • Morningdot Hablu

    Morningdot Hablu

    @morningdot-6Xuj4M Sep 20, 2010

    I am not 100 percent; but i think because computer do our task in hexadecimal format so may this be a reason.
    Correct me if i am wrong.
  • rishi0922

    rishi0922

    @rishi0922-a2xTAa Sep 20, 2010

    n-bit microprocessor means how many bit can a microprocessor can process i.e as the operations.8bit means that microprocessor can process only 8bit addition , subtraction etc as in case.16 bit can process data of 16bit for any kind of operation to be performed.naturally the greater the number of bits to be processed the good it is.
  • shreyasm89

    shreyasm89

    @shreyasm89-jGobVm Sep 20, 2010

    In 8085 or most other mu-p's, the default numbersystem base is hexadecimal.Whatever value we are storing in the registers it has to be in the hex. format. The mu-p will convert it into the equivalent binary & use it for further processing.Also the ALU i.e the accumulator of 8085 is 8-bit i.e. it can perform operations on 8-bit values.
    @rishi-I think most of the ALU's are 8-bit. It is the no. of operation cycles per sec. i.e. the internal oscillator frequency that matters. More no. of oprations will be performed per sec.