6th c++ Problem

have a look of this code

#include<iostream.h>
#define square(x)x*x
void main()
{
int b,a=4;
b=64/square(a);
cout<<b;
}

Tell me the output...?and if it gives wrong output then give me correct output?
ie i want b=4

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  • Mangesh6688
    Mangesh6688

    @mangesh6688-2pfEFZ • Jan 6, 2010

    The output of this program is 64 which is wrong.
    Because the #define square(x) x*x means it will replace the square(x) by x*x
    so in program b=64/square(a) will be replaced by b=64/a*a;
    As in c++ both / and * has equal priority the expression will be as follows:
    b=(64/4)*4; i.e. b=16*4 = 64

    So for getting correct output our program should be 

    #include<iostream.h>
#define square(x) (x*x)
void main()
{
int b,a=4;
b=64/square(a);
cout<<b;
}
    0
  • Manish Goyal
    Manish Goyal

    @manish-r2Hoep • Jan 6, 2010

    yes you are absolutely right

    and nice explanation mangesh

    0