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@jeffrey-xA7lUP • Sep 15, 2012
the answer is simple the amplifier gain at lower cut off and upper cut off frequency is 1/ root 2 times the actual gain in the mid frequency region
the 20(log(1/root2)) is -3 dB
so we use it for drawing the line -
@jeffrey-xA7lUP • Sep 15, 2012
check this out frequency response of lower frequency region
Av=1/(1+j(f/f1))
where f= frequency of the signal
f1= lower cut off frequency
when f=f1
|Av|=1/root(2)
this is also true for higher frequency respone
PS: refer electronic circuits and devices by S. Salivahanan for more info
i took this from there