silverscorpion

Branch Unspecified

10 years ago

I'll just give you the algorithm for now. try coding it yourself.. if you're not able to do it, let's see.

It goes like this:

Initialise 2 counters, let's say i and j.

Use one for printing the numbers in a single line, and the other for the number of lines.

Take care of the spaces in the lines. A simple thing to note is, if there are 'n' lines, then the k-th line has numbers from 1 to k-1, then 2*(k-1)-1 spaces, then numbers from k-1 to 1.

this same algo should work for any pattern, that is, even if the first line is 1234567654321, you can do it by this algo. Just try it.

Hope I'm clear..

It goes like this:

Initialise 2 counters, let's say i and j.

Use one for printing the numbers in a single line, and the other for the number of lines.

Take care of the spaces in the lines. A simple thing to note is, if there are 'n' lines, then the k-th line has numbers from 1 to k-1, then 2*(k-1)-1 spaces, then numbers from k-1 to 1.

this same algo should work for any pattern, that is, even if the first line is 1234567654321, you can do it by this algo. Just try it.

Hope I'm clear..

bROTHER , I ALSO WANT ALMOST THIS KIND OF PROGRAMM BUT I NEED A PYRAMID TO BE PRINTED SAME AS HERE HOW TO KEEP SPACE LOOK MY ONE PROJECT.

----*

---***

--*****

BUT MY ONE IS

*

**

***

****

SO PROBLEM HERE IS SAME

OF YOUR AND MINE CHECKE OUT MY CODE IN MY THERED PRINTING PYRAMID IN VB.

----*

---***

--*****

BUT MY ONE IS

*

**

***

****

SO PROBLEM HERE IS SAME

OF YOUR AND MINE CHECKE OUT MY CODE IN MY THERED PRINTING PYRAMID IN VB.

silverscorpionI'll just give you the algorithm for now. try coding it yourself.. if you're not able to do it, let's see.

It goes like this:

Initialise 2 counters, let's say i and j.

Use one for printing the numbers in a single line, and the other for the number of lines.

Take care of the spaces in the lines. A simple thing to note is, if there are 'n' lines, then the k-th line has numbers from 1 to k-1, then 2*(k-1)-1 spaces, then numbers from k-1 to 1.

this same algo should work for any pattern, that is, even if the first line is 1234567654321, you can do it by this algo. Just try it.

Hope I'm clear..

can u explain it more plzzz

i am unable to get u.

shalini_goel14

Branch Unspecified

10 years ago

Hi disaster

Have a look at following thread, if it can be of any help to you.

https://www.crazyengineers.com/forum/computer-science-engineering/12974-printing-pyramid-vb.html

[Note: Just replace "*" with the counter value you want to print. It is not exactly what you want but logic is almost same.]

You can try once. If an issues let me know.

Have a look at following thread, if it can be of any help to you.

https://www.crazyengineers.com/forum/computer-science-engineering/12974-printing-pyramid-vb.html

[Note: Just replace "*" with the counter value you want to print. It is not exactly what you want but logic is almost same.]

You can try once. If an issues let me know.

disasterguys plz help me to write this progam

123454321

1234 4321

123 321

12 21

the numbers must be printed in this form.😕

/* cinu97@gmail.com */

#include<stdio.h>

int main()

{

int i,j,n;

printf("Enter no");

scanf("%d",&n);

for(i=0;i<n;i++)

{

for(j=1;j<=n-i;j++)

printf("%d",j);

for(j=0;j<((i*2)-1);j++)

printf("*");

for(j=n-i;j>0;j--)

{

if(j==n)

{

}

else

printf("%d",j);

}

printf("\n");

}}

Praveen Kumar Purushothaman

Branch Unspecified

7 years ago

Guys, please refrain from posting EMail addresses in the public forums.

Back to your question, it can be easily achieved by using two counters with a master counter, which counts less. And the same above code with some optimization.

Back to your question, it can be easily achieved by using two counters with a master counter, which counts less. And the same above code with some optimization.

```
#include <stdio.h>
```

int main()

{

int i, j, n;

printf("Enter the number of Lines: ");

scanf("%d", &n);

for(i=0; i<n; i++)

{

for(j=1; j<=n-i; j++)

printf("%d", j);

for(j=0; j<((i*2)-1); j++)

printf("*");

for(j=n-i; j>0; j--)

if(j!=n)

printf("%d", j);

printf("\n");

}

}

andremartin

Branch Unspecified

7 years ago

Use one for printing the numbers in a single line, and the other for the number of lines.

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