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  • Isolation of electric consumption due to CFL

    gaurav2587

    Member

    Updated: Oct 22, 2024
    Views: 1.4K
    Hi all ,
    I have hit a roadblock in my internship project. We are distributing 1 lakh CFLs to residential areas and are expected to measure the acutal usage of these bulbs. It is not posibble to physically take the readings so is there a cost effective way of measuring and monitoring the usage from a remote location or atleast get the cumulative usage at the client location ?
    I was thinking light sensors and transmitters but it is very costly.
    Please help how to acquire the data .
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Replies

  • Saandeep Sreerambatla

    Member • Jun 2, 2010

    I dont know how correct I am! But here is a suggestion.
    Take the power consumed per month of the location before distributing and after distributing then you can get power saved by the CFL's!! this is not efficient though!
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  • gaurav2587

    Member • Jun 3, 2010

    Yes but then the problem will be how to calculate the current usage of bulbs for such a large population ?
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  • aj_onduty

    Member • Aug 25, 2010

    You may feel that I am the most stupid electrical engineer on the face of the earth. But please read this and correct me if you think I am correctible.
    CFLs are known to consume very less power. Typical CFLs used in houses range between 12W and 26W(I use these in my house).Now, lets take an 18W CFL(Average) as an example. In India, we use 230V AC supply. If Power=VI, then current taken by that CFL is .0782A. Now, for an electrical appliance, it is a very small current compared to other lighting systems. If we consider a voltage variation upto 210V, the current consumed is just 0.8A. These may be standardised by the CFL manufacturers themselves, with a very small variation, mey be.
    My point is, what is the need of measuring the current consumed of each and every CFL? Isn't that something tedius and unwanted?I second the idea given by the member English-Scared. Why don't you use that if you have to prove the decrease in energy consumption, rather than measuring the current of every single CFL?
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