Join CrazyEngineers to reply, ask questions, and participate in conversations.
CrazyEngineers powered by Jatra Community Platform
@saandeep-sreerambatla-hWHU1M • Sep 16, 2010
Its 2 Steps above.
@Mona: Good going to keep this initiative active. Could you increase the difficulty level .
@rishi0922-a2xTAa • Sep 17, 2010
its soooo easy mona, so increase the toughness ......./
@chitti-HyCMj0 • Mar 20, 2011
Increased difficulty level....
A and B are participating i a 1500 m race. A gives B a lead of 50 m and beats him by 10 m in a 500 m race. If B completes the 1500 m race in 44 minutes, then A finishes the race.....minutes before B.
1) 2 minutes
2) 12 minutes
3) 14 minutes
4) 20 minutes
@mathbyvemuri-ipvdTv • May 3, 2012
"A gives B a lead of 50 m and beats him by 10 m in a 500 m race"
=> this means, in the same amount of time the distances travelled by A and B are as follows:
distance travelled by A = 500m
distance travelled by B = 450-10 = 440m
=> (Speed of A)/(Speed of B) = 500/440 = 50/44
As the speed and time are inversly proportional for the same amount od distance,
=> (Time taken by A)/(Time taken by B) = 44/50
=> (Time taken by A) = (44/50)(Time taken by B)
This relation holds good for any race, if the speeds of A and B are assuned constant.
"B completes the 1500 m race in 44 minutes"
=> A completes this in = (44/50)*44 = this comes approximately to be 39 minutes
A completes the race 44-39 = 5 minutes before B
Answer is not available in the options, pl check
