Problem in java program

anksinglabyte b=10 shows no error but
float f =10.0 shows error that double found..

why??

see in java by default each decimal value is taken as double so u need to explicitly mention it be ,say 5.98f becoz it wont take it otherwise float,it would take it to be double,similarly byte b=18;here 18 is int by default but its value lies in the range of byte numbers that is we can represent 18 in byte so i hope now u are clear

radha gogiasee in java by default each decimal value is taken as double so u need to explicitly mention it be ,say 5.98f becoz it wont take it otherwise float,it would take it to be double,similarly byte b=18;here 18 is int by default but its value lies in the range of byte numbers that is we can represent 18 in byte so i hope now u are clear

But if 10 is int then it should not be matters that value comes in range of byte or not. Since java does not type demotion.