Need the full working code

Replies

• 

  yamrajbhalla

  any hlp plzzzz
• 

  shalini_goel14

  yamrajbhalla

  any hlp plzzzz

  Please specify in which language you need? 😐
• 

  Raviteja.g

  if you want the code in java here it is
  

  import java.io.*;
  class add
  {
  public static void main(String args[])
  {
  String c1="mohit";
  String c2="bhalla";
  String c3=c1+c2;
  System.out.println(c3);
  
  }
  }

• 

  yamrajbhalla

  #include
  #include
  #include
  
  
  class b
  {
  char nm[30];
  
  public:
  b()
  {strcpy(nm,"unknown");}
  
  b(char nm[])
  {
  strcpy(this->nm,nm);
  }
  
  void setname(char m[])
  {
  strcpy(nm,m);
  }
  
  void print()
  {
  cout< }
  
  b operator +(b c)
  {
  b t;
  char nem[50];
  
  for(int i=0;nm!='\0';i++)
  
  { nem=nm;
  
  
  for(int j=0;c.nm[j]!='\0';j++)
  {nem[i+j+1]=c.nm[j];
  
  } }
  strcpy(t.nm,nem);
  
  
  
  
  
  return t;
  }
  };
  
  
  void main()
  {
  b b1,b2,b3;
  clrscr();
  
  b1.setname("mohit");
  b2.setname("bhalla");
  b3=b1+b2;
• 

  yamrajbhalla

  b1.print();cout<<" + ";b2.print();cout<<" = ";b3.print();
  getch();
  }
  
  
  
  in c++
• 

  yamrajbhalla

  the above code is not wrking good its shhowing mohitbhallaa
  and if i change the second sstring even that its showing me mohitbhallaa
• 

  yamrajbhalla

  i did it thanks aa lott
  but
  now
  the main problem
  
  
  for overloading with - operator
  
  if my frst string s1 = mohitbhalla and
  second string s2 =bhalla
  
  than
  string s3=mohit;
• 

  yamrajbhalla

  please rply ppl
  i need it and i still nt on it
• 

  pradeep_agrawal

  Its always a good practice to first try to solve the problem and then get help if stuck somewhere. We will be more than happy to help in that case.
  
  Could you please post code for overloading the '-' operator for the problem statement and the problem you are facing in getting the desired result.
  
  Note: The logic to solve the issue can be to parse the string s1 for string s2 and if s2 is found then remove s2 from s1 by moving the characters after s2 to the index starting from s2 location.
  
  -Pradeep
• 

  yamrajbhalla

  not getting the desired results
  
  string s1=cooperhead;
  string 2 = head;
  s3=s2-s1;
  but
  output is
  cooperhead
  
  if u have logic than reply please
  
  
  
  

  b operator -(b c)
   { b t;
     char tm[50];
     for(int i=0;i<=(strlen(nm)+1);i++)
       { for(int j=0;j<=(strlen(c.nm)+1);j++)
        if (nm[i]!=c.nm[j])
            tm[i]=nm[i];
  
        }
      strcpy(t.nm,tm);
      return t;

• 

  pradeep_agrawal

  If found multiple issue with the below code:
  
  

  b operator -(b c)
   { b t;
     char tm[50];
     for(int i=0;i<=(strlen(nm)+1);i++)
       { for(int j=0;j<=(strlen(c.nm)+1);j++)
        if (nm[i]!=c.nm[j])
            tm[i]=nm[i];
  
        }
      strcpy(t.nm,tm);
      return t;
  

  The issues are:
  - You are running a loop from 0 to (strlen of string + 1). The (strlen + 1) represent some garbage character. The loop should be run for 0 to i (and j) < (strlen of string).
  - After above changes the problem will stuck due to inner loop always starting checking from 0. This will assign the whole string of s1 to temprary array tm (except the characters present in s2), e.g., if s2 is "cooperhead" and s2 is "head", the updated code will result in a string "coopr", i.e., an extra e will get deleted. For this the inner loop should be modified to run from "i to < strlen" and ignore characters in the s1 only if the complete string s2 is found and not if any character of s2 is found.
  - After above changes the strcpy function may throw error because the string array "tm" is not ended by end of string character '/0'. You should do that before the stcpy statement as "tm = '/0';"
  
  Try above changes and I feel that should make your code working.
  
  Let us know if you face issue even after above changes.
  
  A query on the problem statement
  1. Will s2 always appear at end of s1 like "cooperhead" has "head" at the end. If this is the problem statement then the problem can be more easily solved by checking if s2 is present at end of s1 and if yes the just copy s1 to tm and do "tm[strlen(s1) - stelen(s2)] = '/0';"
  
  2. Or can s2 be anywhere in s1, e.g, s1 is "cooperhead-head2"? If this is the problem statement then the approach you are currently following should be followed. But then depending on what should be removed on running the program as
  - all instances of "head"?
  - or only first instance of "head"?
  - or only last instance of "head"?
  the code will change.
  
  -Pradeep