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@thebigk • Oct 19, 2014
I'm typing it for the benefit of the community here 😀
It is desired to extract maximum power of 3 from 24! where n! = n.(n-1).(n-2)...3.2.1. What will be exponent of 3?
Options:
a) 8 b) 9 c) 11 d)10
Since this is a math question, I'm moving this to proper section. Also updated the title to make it obvious to know what's the question about. -
@ramani-VR4O43 • Oct 19, 2014
The factors must be themselves multiples of 3. In this case these are: 3, 6, 9, 12, 15, 18, 21 & 24.
the powers of 3 in these are, 1, 1, 2, 1, 1, 2, 1 &1 respectively.
The highest power of three that can be got by a product of these 8 factors is the sum of the 8 powers = 10. -
@satyam-P9vodx • Sep 12, 2018
