15 Jun 2006

# Try The 'C' Code !

Here comes a challenge for Computer Engineers !

int i, n = 20;
for (i = 0; i < n; i--)
{
printf("X");
}

By only changing or adding ONLY ONE character to the above code:

Find 3 ways to make the above code print X 20 times!

-The Big K-
p.s: This challenge will be open for all CEans untill someone cracks it. Do *not* expect an answer from me.

sristi

Branch Unspecified
15 Jun 2006
1)
int i, n = 20;
for (i = 0; i < n; i++)
{
printf("X");
}

2)int i,n=20;
for(i=0;i++<n😉
{
print("X");
}

3)
int i, n = 20;
for (i = 0; ++i < =n; )
{
printf("X");
}
15 Jun 2006
That was a nice attempt

But you missed this -

By only changing or adding ONLY ONE character to the above code:
😉

-The Big K-

Jerry

Branch Unspecified
15 Jun 2006
working on it

sristi
1)
int i, n = 20;
for (i = 0; i < n; i++)
{
printf("X");
}
yeh, you changed -- to ++ , that is you changed two characters. However you are allowed to change only one chracter from the code. Really interesting, I'm working on it !😉

crook

Branch Unspecified
16 Jun 2006
I'm not a C programmer but this is more of a logic problem. Should not take more time. Let me see what can I do about it.

crook
17 Jun 2006
probably I should start giving out hints!

Cummont fellaz, do you really need them?

-The Big K-

crook

Branch Unspecified
17 Jun 2006
got it

i think i got it.

in the original code, make the following change

for (i = 0; i < n; n--)

it should work! now trying the remaining two methods 😁

crook

Branch Unspecified
25 Jun 2006
here comes the second way - 😁

int i, n = 20;
for (i = 0; -i < n; i--)
{
printf("X");
}
and the third 😁

int i, n = 20;
for (i = 0; i + n; i--)
{
printf("X");
}

crook

Branch Unspecified
25 Jun 2006
New Challenge !

This is a simple C puzzle for you -

"Write a "Hello World" program in 'C' without using a semicolon."

Try it, its very simple.

CrooK

Jerry

Branch Unspecified
25 Jun 2006
int i, n = 20;
for (i = 0; -i < n; i--)
{
printf("X");
}

will this work? 😒

I don't have a compiler to try this out. I have started working on crook's problem. Its been quite sometime since I letf coding 😔

Branch Unspecified
28 Jun 2006
main(){if(printf("Hello world")){}}

This might print hello world. No semi-colons used.

crook

Branch Unspecified
28 Jun 2006
yes, thats a correct solution! 😀

rajeshkumar.km

Branch Unspecified
07 Aug 2006
my guesss

😉
int i, n = -20;
for (i = 0; i < n; i--)
{
printf("X");
}

i think the above change ( minus sign before 20 in the line 'int i,n=20')will respond to your view correctly

crook

Branch Unspecified
08 Aug 2006
rajeshkumar.km
😉
int i, n = -20;
for (i = 0; i < n; i--)
{
printf("X");
}

i think the above change ( minus sign before 20 in the line 'int i,n=20')will respond to your view correctly
😕 I'm afraid the logic won't work.

Croook

Branch Unspecified
10 Aug 2006
ans:

first method:

int i, n = -20;
for (i = 0; i < n; i--)
{
printf("X");
}

second method :

int i, n = 20;
for (i = 0; i < -n; i--)
{
printf("X");
}

third method:

int i, n = 20;
for (i = 20; i < n; i--)
{
printf("X");
}

😁

Mahesh

Branch Unspecified
07 Oct 2006
third method:

int i, n = 20;
for (i = 20; i < n; i--)
{
printf("X");
}

How can this work? This is an infinite loop.
07 Oct 2006
Mahesh
third method:

int i, n = 20;
for (i = 20; i < n; i--)
{
printf("X");
}

How can this work? This is an infinite loop.
` for (i = 20; i < n; i--)`
Good Catch, Mahesh 😀 . Devi Prasad might want to fix it.

-The Big K-

bantini

Branch Unspecified
10 Oct 2006
how about (i=0;i<n:-i--)?😕 hey dude,just a lame attempt from an amateur!!!dunno much about c anyway!

Branch Unspecified
11 Oct 2006
Mahesh
third method:

int i, n = 20;
for (i = 20; i < n; i--)
{
printf("X");
}

How can this work? This is an infinite loop.
I don't think there's an infinite loop in the code. Infact, statements inside loop are not executed even once.

n=20, i=20 at initilization and condition is i<n, 20<20 is not true. Condition fails straightaway.

Mahesh

Branch Unspecified
11 Oct 2006
Still the program is wrong.Can you give correct solution?

Branch Unspecified
18 Oct 2006
/* 1st Way: Change i in i-- by n*/
int i, n = 20;
for (i = 0; i < n; n--)
{
printf("X");
}

/* 2nd Way: Add - before i in i < n */
int i, n = 20;
for (i = 0; -i < n; i--)
{
printf("X");
}

/* 3rd Way: Change < in i < n by + */
int i, n = 20;
for (i = 0; i + n; i--)
{
printf("X");
}

Branch Unspecified
19 Oct 2006
This is decent enough, hope the 3 ways are as follows -

int i, n = 20;
for (i = 0; i < -n; i--)
{
printf("X");
}

int i, n = 20;
for (i = 40; i < n; i--)
{
printf("X");
}

int i, n = 20;
for (i = 0; i > n; i--)
{
printf("X");
}

I have indicated in red the change in character that I have made.

ksrbhanu

Branch Unspecified
03 Nov 2006
Hi friends,

I have one method, i will try other two. mean while review this method

int i, n = 20;
for (i = 0; i < n; n--)
{
printf("X");
}

replacing the i in the decrement statement with n it works , this is one character change 😎

ksrbhanu

Branch Unspecified
03 Nov 2006
sory guys, i have n't checked the whole chain , pradeep has already posted this metho 😔

spirit

Branch Unspecified
09 Nov 2006
hello.....i m giving your answer n u have to tell thats right or not.....😎
int i, n = 20;
for (i = 0; i < n; i--)
{
printf("X");
}
1. instead of i-- in the loop,change it as n--.
2.in initialisation,n=20,change it as:n=-20.

😁

rahul dev choud

Branch Unspecified
16 Jan 2007
hey its really interesting don't tell da ans...

working on it ....

w'll back soon......